D. You are running a 4500-foot race. How much farther
1 answer:
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Equations with absolute value:
Where k is a positive number; if k is a negative number, the equation is impossible (absolute value is always positive).
How to solve:
Then:
1. |x+7|=12
x+7=12 V -x-7=12
x=5 V -x=19
x=5 V x=-19
{-19, 5}
2. |2x+4|=8
2x+4=8 V -2x-4=8
2x=4 V -2x=12
x=2 V x=-6
3. 3|3k|=27
3×3k=27 V 3×(-3k)=27
9k=27 V -9k=27
k=3 V k=-3
{-3, 3}
4. 5|b+8|=30
5×(b+8)=30 V 5×(-b-8)=30
5b+40=30 V -5b-40=30
5b=-10 V -5b=70
b=-2 V b=-14
{-14, -2}
5. |m+9|=5
m+9=5 V -m-9=5
m+9=5 V m+9=-5
Where k is a positive number; if k is a negative number, the equation is impossible (absolute value is always positive).
How to solve:
Then:
1. |x+7|=12
x+7=12 V -x-7=12
x=5 V -x=19
x=5 V x=-19
{-19, 5}
2. |2x+4|=8
2x+4=8 V -2x-4=8
2x=4 V -2x=12
x=2 V x=-6
3. 3|3k|=27
3×3k=27 V 3×(-3k)=27
9k=27 V -9k=27
k=3 V k=-3
{-3, 3}
4. 5|b+8|=30
5×(b+8)=30 V 5×(-b-8)=30
5b+40=30 V -5b-40=30
5b=-10 V -5b=70
b=-2 V b=-14
{-14, -2}
5. |m+9|=5
m+9=5 V -m-9=5
m+9=5 V m+9=-5
Answer:
x=30
Step-by-step explanation:
Since this a regular hexagon, each angle measure is congruent.
A hexagon interior angles add to be
(
However, in the triangle, only part of angle b and angle f is in the triangle. However angle a is fully in the triangle so
Angle A=120.
So using the triangle interior theorem, angle b and f must add up to 180.
However, since this is a regular hexagon, the sides are equal so this is a isoceles triangle.
Using the base isoceles triangle theorem, angle b and angle f of the triangle must be equal so
Answer: