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Alex787 [66]
3 years ago
13

The figure in quadrant III it the coordinate plane below is a transformation of the figure in quadrant II. The figure in quadran

t III is a _______ of Quadrant II.

Mathematics
2 answers:
tankabanditka [31]3 years ago
8 0

Answer:

reflection

i am not sure if i am correct but hope this helps.

Step-by-step explanation:


brilliants [131]3 years ago
4 0

Answer:

Option: B is the correct answer.

B. Reflection.

Step-by-step explanation:

Clearly from the figure we could observe that the figure in quadrant III is obtained by reflecting the figure in the II quadrant across x-axis.

and hence, the points of the figure are reflected by the rule:

(x,y) → (x,-y).

Also ,

8→e

4→a

3→b

7→f

Similarly the upper half of the figure of second quadrant goes to the lower half of figure in the third quadrant.

Hence, option: B is the correct answer.

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F(x) = -7x - 19<br>g(x) = 0.75x + 4.25 <br>x=​
Xelga [282]

Answer:x=-14.75

Step-by-step explanation:

f(x) = -7x - 19=-19

g(x) = 0.75x + 4.25 =4.25

5 0
2 years ago
What is the solution to this equation?
Komok [63]

Answer:

B. x=75

Step-by-step explanation:

First, write out the equation as you have it:

x/5=15

Then, multiply both sides of the equation by 5/1:

5/1(x/5)=15(5/1)

Your result is:

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5 0
3 years ago
On 1 May 2012, the cost of 5 grams of gold was 14 000 rupees.
navik [9.2K]

Answer:

51,800 rupees

Step-by-step explanation:

Cost of 5 grams of gold on 1 May 2012 = 14 000 rupees.

The cost of gold decreased by 7.5% from 1 May 2012 to 1 May 2013

Cost of 5 grams of gold on 1 May 2013 = 14,000 - 7.5% of 14,000

= 14,000 - 0.075 × 14,000

= 14,000 - 1,050

= 12,950 rupees

Work out the cost of 20 grams of gold on 1 May 2013

Since, there are four 5 grams of gold in 20 grams of gold

Therefore,

Cost of 20 grams of gold on 1 May 2013 = 12,950 rupees × 4

= 51,800 rupees

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12/5 - 3/10 = 24-3 /10 = 21/10

OR 2.1 in decimal form

6 0
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