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klasskru [66]
3 years ago
12

Solve this application problem using a system of equations: The Springfield Movie Theater sold adult tickets for $4.10 each and

children's tickets for $2.70 each. Last Thursday, a total of $331.30 was collected from 89 movie watchers. How many of each type of ticket were sold on Thursday?
Mathematics
1 answer:
soldi70 [24.7K]3 years ago
7 0

Answer: 65 adult ticket and 24 children's ticket

Step-by-step explanation:

Let the total number of adults be x

And the total number of children be y

The cost of ticket for 1 adult = $4.10 , this means that the cost of ticket for x adults will be 4.10x

The cost of ticket for a child = $2.70 , this means that the cost of ticket for y children will be 2.70y.

The total sale was $331.30 , that is

4.10x + 2.70y = 331.30

Total number of movie watchers were 89 , that is

x + y = 89

Combining the two equations , we have :

x + y = 89 ......................... equation 1

4.10x + 2.70y = 331.30 .................. equation 2

solving the system of linear equation by substitution method.

From equation 1 , make x the subject of the formula

x = 89 - y ........................... equation 3

substitute x = 89 - y into equation 2 , equation 2 then becomes

4.10(89 - y ) + 2.70y = 331.30

expanding the bracket , we have

364.9 - 4.10y + 2.70y = 331.30

364.9 - 1.4y = 331.30

collecting the like terms , we have

364.9 - 331.30 = 1.4y

33.6 = 1.4y

divide through by 1.4

33.6/1.4 = y

Therefore : y = 24

substitute y = 24 into equation 3

x = 89 - y

x = 89 - 24

x = 65

Therefore , there were 65 adults and 24 children ticket sold

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