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3 years ago

Im desperate like most of my question-

Mathematics

2 answers:

-Dominant- [34]3 years ago

8 0

Answer:

$5.25

Step-by-step explanation:

kvv77 [185]3 years ago

7 0

<h3>Answer: 9.75 dollars</h3>

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Explanation:

There are two ways to solve this problem.

Method 1:

35% = 35/100 = 0.35

35% of 15 = 0.35*15 = 5.25

So you save $5.25, which is the discount amount.

The sale price is 15 - 5.25 = 9.75 dollars

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Method 2:

If you save 35%, then you still need to pay the remaining 65%

35% + 65% = 100%

The sale price is 65% of original price

sale price = 65% of original price

sale price = 0.65*15

sale price = 9.75 dollars

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Extra info (optional section)

The benefit of method 2 is that we can chain multiple discounts together. Consider that on top of the 35% discount, the store then decides that members (people who pay monthly) will get an extra 10% off. The natural thinking is that the total discount is 35%+10% = 45% off, but that's not correct.

We can see this if we say that the original price is say $100 and 35% off would lead to a price of 0.65*100 = 65 dollars. Then an extra 10% off means we pay 90% of that new price (65 dollars) to get 0.90*65 = 58.50

As a shortcut, we can just multiply the values of 0.65*0.90 = 0.585

Then note how 100*0.585 = 58.50 showing us a fairly fast way to compute the final sale price even if multiple discounts are applied. This can be extended to more discounts. Again, we do not add the percentages when it comes to figuring out how much the total discount percentage would be.

Since the item was $100 but now it's 58.50, this means we saved 100-58.50 = 41.50 dollars. The discount is therefore 41.50/100 = 41.50% which is close to the 45% calculated earlier, but not quite there.

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Lady bird [3.3K]

Answer: 3X+4 is the correct answer

Step-by-step explanation:

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3 years ago

Find the slope between the two points given. Then, use the slope and the first point to write the equation of the line in Point-

Vera_Pavlovna [14]

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3 years ago

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The tensile strength of stainless steel produced by a plant has been stable for a long time with a mean of 72 kg/mm2 and a stand

Elanso [62]

Answer:

95% confidence interval for the mean of tensile strength after the machine was adjusted is [73.68 kg/mm2 , 74.88 kg/mm2].

Yes, this data suggest that the tensile strength was changed after the adjustment.

Step-by-step explanation:

We are given that the tensile strength of stainless steel produced by a plant has been stable for a long time with a mean of 72 kg/mm 2 and a standard deviation of 2.15.

A machine was recently adjusted and a sample of 50 items were taken to determine if the mean tensile strength has changed. The mean of this sample is 74.28. Assume that the standard deviation did not change because of the adjustment to the machine.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean strength of 50 items = 74.28

$\sigma$ = population standard deviation = 2.15

n = sample of items = 50

$\mu$ = population mean tensile strength after machine was adjusted

Here for constructing 95% confidence interval we have used One-sample z test statistics as we know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level of

significance are -1.96 & 1.96}

P(-1.96 < $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $74.28-1.96 \times {\frac{2.15}{\sqrt{50} } }$ , $74.28+1.96 \times {\frac{2.15}{\sqrt{50} } }$ ]

= [73.68 kg/mm2 , 74.88 kg/mm2]

Therefore, 95% confidence interval for the mean of tensile strength after the machine was adjusted is [73.68 kg/mm2 , 74.88 kg/mm2].

Yes, this data suggest that the tensile strength was changed after the adjustment as earlier the mean tensile strength was 72 kg/mm2 and now the mean strength lies between 73.68 kg/mm2 and 74.88 kg/mm2 after adjustment.

8 0

4 years ago

Plzzzzzzzzz help meeeeeeeeeeeeee

zzz [600]

Answer:

Solution; x = - 2, x = 5

Step-by-step explanation:

We are given the following equation 2x^2 + 2x + 12 = 3x^2 - x + 2;

2x^2 + 2x + 12 = 3x^2 - x + 2 ⇒ Subtract 2 from either side,

2x^2 + 2x + 10 = 3x^2 - x ⇒ Add x on either side,

2x^2 + 2x + 10 = 3x^2 ⇒ Subtract 3x^2 on either side, simplifying result,

- x^2 + 3x + 10 = 0 ⇒ Factor out common term - 1,

- ( x^2 - 3x - 10 ) = 0 ⇒ Break expression into groups,

- ( x^2 + 2x ) + ( - 5x - 10 ) = 0⇒ Factor x from x^2 + 2x , and - 5 from - 5x - 10,

- ( x( x + 2 ) ) - 5( x + 2 ) = 0 ⇒ Factor out common term x + 2,

- ( x + 2 )( x - 5 ) = 0 ⇒ Apply Zero Factor Principle,

x + 2 = 0, and x - 5 = 0 ⇒ Simplify,

Solution; x = - 2, x = 5

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3 years ago

There are 7 days in 1 week. How many days are there in 4 weeks?

Sever21 [200]

Hey! This is a very simple question, let me walk you through.

1 week = 7 days.

7 days, multiplied by 4 weeks, is 28.

This means, 28 days are in 4 weeks.

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4 years ago

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