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OverLord2011 [107]
3 years ago
14

Which of the following is the conjugate of 10 – 3i?

Mathematics
2 answers:
wariber [46]3 years ago
7 0
10 + 3i ...........................
ipn [44]3 years ago
3 0

we know that

The conjugate of a complex number is the number with equal real part and imaginary part equal in magnitude but opposite in sign

so

In this problem we have

10-3i

the conjugate is equal to--------> 10+3i

therefore

<u>the answer is the option</u>

10+3i

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WILL MARK BRAINLYIEST
Eddi Din [679]
Hello, and thank you for posting your question here on brainly.

When you're dividing two fractions, there's a simple rule to follow.

You flip the second fraction, (aka reciprocal) and then multiply.

2/3 ÷ 1/4 = 2/3 * 4/1

You multiply across from the top and bottom.

2/3 * 4/1 = 8/3

8/3 = 2 2/3

Your final answer is C.

Hope this helps! ☺♥
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3 years ago
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A recipe calls for 10 cups of sugar for every 3 eggs. How many cups of sugar are
sweet [91]

Answer:

40 cups of sugar

Step-by-step explanation:

10 cups = 3 eggs

x cups = 12 eggs( a dozen )

12*10 =3x

120=3x

120/3=40

6 0
3 years ago
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The game of clue involves 6 suspects, 6 weapons, and 9 rooms. one of each is randomly chosen and the object of the game is to gu
mina [271]
Part A:

Given that t<span>he game of clue involves 6 suspects, 6 weapons, and 9 rooms.

The number of ways that one of each is randomly chosen is given by:

^6C_1\times{ ^6C_1}\times{ ^9C_1}=6\times6\times9=324

Therefore, the number of solutions possible is 324.



Part B:

Given that a </span>players is randomly given three of the remaining cards, <span>let s, w, and r be, respectively, the numbers of suspects, weapons, and rooms in the set of three cards given to a specified player.

The number of suspects, weapons, and rooms remaining respectively after the player observes his or her three cards are: 6 - s, 6 - w, and 9 - r.

Let x denote the number of solutions that are possible after that player observes his or her three cards, then:

x={ ^{6-s}C_1}\times{ ^{6-w}C_1}\times{ ^{9-r}C_1}=(6-s)(6-w)(9-r)

Therefore, x in terms of s, w, and r is given by x = (6 - s)(6 - w)(9 - r).



Part C:

The expected value E(x) of a data set x_i with probabilities p(x_i) is given by E(x)=\Sigma xp(x)

There are </span>^{3+3-1}C_{3-1}={ ^5C_2}=10 possible combinations s, w and r. They are (3, 0, 0), (0, 3, 0), (0, 0, 3), (2, 1, 0), (0, 2, 1), (1, 0, 2), (2, 0, 1), (1, 2, 0), (0, 1, 2), (1, 1, 1)

Thus the expected value is given by

E(x)=3\cdot6\cdot9p(3, 0, 0)+6\cdot3\cdot9p(0, 3, 0)+6\cdot6\cdot6p(0, 0, 3) \\ 4\cdot5\cdot9p(2, 1, 0)+6\cdot4\cdot8p(0, 2, 1)+5\cdot6\cdot7p(1, 0, 2)+4\cdot6\cdot8p(2, 0, 1) \\ +5\cdot4\cdot9p(1, 2, 0)+6\cdot5\cdot7p(0, 1, 2)+5\cdot5\cdot8(1, 1, 1) \\  \\ = \frac{1}{ ^{21}C_3} (162\cdot{ ^6C_3}\cdot{ ^6C_0}\cdot{ ^9C_0}+162\cdot{ ^6C_0}\cdot{ ^6C_3}\cdot{ ^9C_0}+216\cdot{ ^6C_0}\cdot{ ^6C_0}\cdot{ ^9C_3} \\ \\ +180\cdot{ ^6C_2}\cdot{ ^6C_1}\cdot{ ^9C_0}+192\cdot{ ^6C_0}\cdot{ ^6C_2}\cdot{ ^9C_1}

+210\cdot{ ^6C_1}\cdot{ ^6C_0}\cdot{ ^9C_2}+192\cdot{ ^6C_2}\cdot{ ^6C_0}\cdot{ ^9C_1}+180\cdot{ ^6C_1}\cdot{ ^6C_2}\cdot{ ^9C_0} \\  \\ +210\cdot{ ^6C_0}\cdot{ ^6C_1}\cdot{ ^9C_2}+200\cdot{ ^6C_1}\cdot{ ^6C_1}\cdot{ ^9C_1} \\  \\ =\frac{1}{1,330}(324\cdot20+216\cdot84+360\cdot90+384\cdot135+420\cdot216+200\cdot324) \\  \\ =\frac{1}{1,330}(6,480+18,144+32,400+51,840+90,720+64,800) \\  \\ =\frac{1}{1,330}(264,384) \\  \\ =\bold{198.78}
6 0
3 years ago
Express the area of the entire rectangle
Ludmilka [50]

Answer:

x^2 + 6x + 8

Step-by-step explanation:

area of blue = x^2

area of pink= 2x

area of green=4x

area of brown=8

Adding all the area.

we get : x^2 + 6x +8

8 0
3 years ago
Given that P(BA) means the probability of event B occurring given that event A will occur or has occurred, which of the followin
Westkost [7]
The correct answer is D
3 0
3 years ago
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