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MAVERICK [17]
3 years ago
12

What are two answers for 2 / 3 - 5 / 12

Mathematics
1 answer:
nordsb [41]3 years ago
6 0

Answer:

0.25

Step-by-step explanation:

the answer is 1/4 or 0.25 in decimal form

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what's the surface area of this square pyramid that has a base length of 5 inches and triangular faces that are 9 inches tall
Vadim26 [7]

The surface area of the square prism is 115 square inches

<h3>surface area of a pyramid</h3>

The surface area of a pyramid is equivalent to the sum of the faces of the pyramid

For the given square pyramid;

TSA = (5*5) + 4(1/2 * 9 * 5)

Simplify to have;

Surface area =25 + 4(45/2)

Surface area = 25 + 180/2

Surface area = 25. + 90

Surface area = 115 square inches

Hence the surface area of the square prism is 115 square inches

Learn more on surface area here: brainly.com/question/20771646

#SPJ1

7 0
1 year ago
What is the domain of the function?
boyakko [2]
(-infinity, +infinity)
5 0
3 years ago
PLZ HELP FAST!!!! WILLL GIVEE BRANILIESTTTTT!!Which of the following best describes the pyramid represented by this net? square
DedPeter [7]

Answer:

How can send/put/mark someone braniliest

7 0
3 years ago
?÷(−7)=(−4) what is the missing number
Hunter-Best [27]

Answer:

The answer is 28.

Step-by-step explanation:

To find the solution, you must multiply the other two numbers together to find the original number that is divided.

-7 * -4 = 28 Answer

28/-7 = -4

Hope this helps!

3 0
3 years ago
Read 2 more answers
A network provider investigates the load of its network. The number of concurrent users is recorded at fifty locations (thousand
beks73 [17]

Answer:

see explaination

Step-by-step explanation:

Using the formulla that

sum of terms number of terms sample mean -

Gives the sample mean as \mu=17.954

Now varaince is given by

s^2=\frac{1}{50-1}\sum_{i=1}^{49}(x_i-19.954)^2=9.97

and the standard deviation is s=\sqrt{9.97}=3.16

b) The standard error is given by

\frac{s}{\sqrt{n-1}}=\frac{3.16}{\sqrt{49}}=0.45

c) For the given data we have the least number in the sample is 12.0 and the greatest number in the sample is 24.1

Q_1=15.83, \mathrm{Median}=17.55 and Q_3=19.88

d) Since the interquartile range is Q_3-Q_1=19.88-15.83=4.05

Now the outlier is a number which is greater than 19.88+1.5(4.05)=25.96

or a number which is less than 15.83-1.5(4.05)=9.76

As there is no such number so the given sample has no outliers

5 0
3 years ago
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