First we rearrange by using the definition of between.
AB=x+10, BC=x+14, AC=22
Given that AB+BC=AC, we can solve for X
(X+10)+(X+14)=22
X+10+X+14=22
2X+24=22
2X+24-24=22-24
2X=-2
2X/2=-2/2
X= -1
Answer:
The answer to your question is letter A (2/3)
Step-by-step explanation:
Formula
tangent Ф = 
For A
opposite side = 2
adjacent side = 3
Substitution
tan Ф = 
Result
tan Ф =
The answer is 56.
I know this because...
<span>-6 + {14 + 2 [60 − 9(1 + 3)]}
-6 + </span>{14 + 2[60 − 9(4)]}
-6 + {14 + 2[60 − 36]}
-6 + {14 + 2[24]}
-6 + {14 + 48}
-6 + {62}
-6 + 62 = 56
Answer:
Given the domain, the range for 3x-y = 3 is {-9, 6, 9}
Step-by-step explanation:
First you have to put the relation in terms of y ⇒ 3x - y = 3⇒ 3x -3 = y
⇒ y = 3x - 3.
Then you replace the values indicated by the domain to find their "y" values (the ones that constitute the range).
f(-2) = -9
f(2) = 6
f(4) = 9.
Finally, the range for the given domain is {-9, 6, 9}
