The polar head of a phospholipid is made of phosphate. The polar head has a negative charge that is made up of phosphate molecules. This polar region attracts water and is positioned outward to interact with the water.
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Answer:
Alleles for feather colour exhibit incomplete dominance or co-dominance.
50% gray offspring + 50% black offspring
Explanation:
<em>It means that the alleles for feather colour in the hen exhibit incomplete dominance or co-dominance over one another.</em>
Assuming the allele for white colour is B, white colour will be b while the heterozygote Bb gives the gray phenotype.
Gray rooster + gray hen = 15 gray chicks, 6 black chicks and 8 white chicks.
15:6:8 is roughly 2:1:1 which is phenotypic ratio obtainable from crossing two heterozygous individuals as pointed out by Mendel.
Bb x Bb = 1BB, 2Bb, and 1bb
Crossing the gray rooster (Bb) with a black hen (bb):
Bb x bb = Bb, Bb, bb, and bb
= 2Bb (gray):2bb (black)
50% of the offspring will be gray while the remaining 50% will be black.
Answer:
B. 50 mM glucose; E. 300 mM glucose
Explanation:
In order for the cell to shrink the concentration of solutes in the blood should be above normal or higher than the intracellular concentration, so that water moves from the inside of the cell to the outside by the process known as osmosis.
The normal blood levels of NaCl = ~ 154 mM; therefore A, C and D will not cause any shrinkage.
The normal blood levels of glucose = ~ 3.9 to 7.1 mM; therefore water would move from the intracellular to the extracellular space since the solutes are 10x higher outside the cell, causing shrinkage of the cell.
