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Mashutka [201]
3 years ago
15

A spherical raindrop 2.5 mm in diameter falls through a vertical distance of 3900 m. Take the cross-sectional area of a raindrop

= πr2, drag coefficient = 0.45, density of water to be 1000 kg/m3, and density of air to be 1.2 kg/m3. (a) Calculate the speed (in m/s) a spherical raindrop would achieve falling from 3900 m in the absence of air drag. m/s
Physics
1 answer:
Karolina [17]3 years ago
5 0

Answer:

276.62 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s² (positive downward and negative upward)

Equation of motion

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 9.81\times 3900+0^2}\\\Rightarrow v=276.62\ m/s

<u>Neglecting air drag</u> the velocity of the spherical drop would be 276.62 m/s

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Answer:

Mass, m = 6.18 kg

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Given the following data;

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To find the mass, we would use the following formula;

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Where;

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Substituting into the formula, we have;

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10 = 22/14 * √250/m

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140 = 22 * √250/m

Dividing both sides by 22, we have;

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6.36² = (√250/m)²

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40.45m = 250

Mass, m = 250/40.45

Mass, m = 6.18 kg

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2 years ago
Find the average force exerted by the bat on the ball if the two are in contact for 0.00129 s. Answer in units of N.
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Answer:

Explanation:

Given

time of contact between bat and ball is t=0.00129 s

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