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3 years ago

What’s a good hypothesis and and experiment for water?

Physics

1 answer:

Lelu [443]3 years ago

6 0

Answer: You could do something like, "how does water react to being mixed with baking soda"...or something along those lines

Explanation:

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On average, both arms and hands together account for 13% of a person's mass, while the head is 7.0% and the trunk and legs accou

Feliz [49]

Answer:

Angular velocity, $N_f = 242.36 rpm$

Explanation:

The mass of the skater, M = 74.0 kg

Mass of each arm, $m_{a} = 0.13 * \frac{M}{2}$ ( since it is 13% of the whole body and each arm is considered)

$m_{a} = 0.13 * 37\\m_a = 4.81 kg$

Mass of the trunk, $m_{t} = M - 2m_{a}$

$m_t = 74 - 2(4.81)\\m_{t} = 64.38 kg$

Total moment of Inertia = (Moment of inertia of the arms) + (Moment of inertia of the trunks)

$(I_{T} )_i = 2(\frac{m_{a}L^2 }{12} + m_a(0.5L + R)^2) + 0.5 m_t R^2$

$(I_{T} )_i = 2(\frac{4.81 * 0.7^2 }{12} + 4.81(0.5*0.7 + 0.175)^2) + 0.5 *64.38* 0.175^2\\(I_{T} )_i = 3.052 + 0.986\\(I_{T} )_i = 4.038 kgm^2$

The final moment of inertia of the person:

$(I_{T} )_f = \frac{1}{2} MR^{2} \\(I_{T} )_f = \frac{1}{2} * 74*0.175^{2}\\(I_{T} )_f = 1.133 kg.m^2$

According to the principle of conservation of angular momentum:

$(I_{T} )_i w_{i} = (I_{T} )_f w_{f}\\w_{i} = 68 rpm = (2\pi * 68)/60 = 7.12 rad/s\\4.038 * 7.12 =1.133* w_{f}\\w_{f} = 25.38 rad/s\\w_{f} = \frac{2\pi N_f}{60} \\25.38 = \frac{2\pi N_f}{60}\\N_f = (25.38 * 60)/2\pi \\N_f = 242.36 rpm$

3 0

3 years ago

Two cubes, one silver and one iron, have the same mass and temperature. A quantity Q of heat is removed from each cube. Which on

scoundrel [369]

Answer:

C) specific heat capacity

Explanation:

As we know that heat given to the system to change the temperature is given as

$Q = ms \Delta T$

here we know that

Q = thermal energy given to the system

s = specific heat capacity of the system

$\Delta T$ = change in temperature

so here we know that

$\Delta T = \frac{Q}{ms}$

here we know that heat given to the two cubes is of same amount as well as the mass is same but the final temperature is different because of the specific heat capacity (s)

So correct answer would be

C) specific heat capacity

8 0

3 years ago

Bru this was a challenge......but

anygoal [31]

Answer:

Free points

Explanation:

6 0

3 years ago

Read 2 more answers

A projectile (mass = 0.15 kg) is fired at and embeds itself in a stationary target (mass = 2.44 kg). With what percentage of the

Bess [88]

Answer:

38.6 %

Explanation:

First of all, we have to calculate the final velocity of the block-bullet system. We can apply the law of conservation of momentum:

$m u + M U = (m+M)v$

where

m = 0.15 kg is the mass of the bullet

u is the initial velocity of the bullet

M = 2.44 kg is the mass of the block

U = 0 is the initial velocity of the block (it is at rest)

v is the final velocity of the bullet+block

Solving for v,

$v=\frac{mu}{m+M}$

The total initial kinetic energy of the system is just the kinetic energy of the bullet:

$K = \frac{1}{2}mu^2$

While the final kinetic energy of the block+bullet is:

$K' = \frac{1}{2}(m+M) v^2 = \frac{1}{2}(m+M) \frac{(mu)^2}{(m+M)^2}=\frac{1}{2} \frac{m}{m+M}u^2$

So the fraction of kinetic energy lost is

$\frac{K-K'}{K}=\frac{\frac{1}{2}mu^2 - \frac{1}{2}\frac{m}{m+M}u^2}{\frac{1}{2}mu^2}=\frac{m-\frac{m}{m+M}}{m}=\frac{0.15-\frac{0.15}{0.15+2.44}}{0.15}=0.614$

And so, the fraction of kinetic energy left in the projectile after he flies off the block is

1 - 0.614 = 0.386 = 38.6 %

4 0

3 years ago

A car pulling out of a gas station accelerates from rest at a constant rate it covers 1200 meters in 30 seconds. What is the rat

Goshia [24]

The car accelerates at 40 meters per second.

3 0

3 years ago