Measurements of two electric currents are shown in the chart. A 3-column table with 2 rows titled Electric Currents. The first c
2 answers:
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Answer:
12.5752053801 m/s
No.
Explanation:
Q = Volume flow rate =
d = Diameter of pipe = 9 cm
A = Area =
Volume flow rate is given by
Velocity of fluid is 12.5752053801 m/s
The volume flow rate in m³/s is
The flow of fluid does not depend on the type of water used. Hence the answers would be same. If Q is constant v will be the same irrespective of the type of water used.
Answer:
The centripetal acceleration for the first radius; 2.0 m = 50 m/s²
The centripetal acceleration for the second radius; 4.0 m = 25 m/s²
The centripetal acceleration for the third radius; 6.0 m = 16.67 m/s²
The centripetal acceleration for the fourth radius; 8.0 m = 12.5 m/s²
The centripetal acceleration for the fifth radius; 10.0 m = 10 m/s²
Explanation:
Given;
mass of the object, m = 1 kg
velocity of the object, v = 10 m/s
different values of the radius, 2.0 m 4.0 m 6.0 m 8.0 m 10.0 m
The centripetal acceleration for the first radius; 2.0 m
The centripetal acceleration for the second radius; 4.0 m
The centripetal acceleration for the third radius; 6.0 m
The centripetal acceleration for the fourth radius; 8.0 m
The centripetal acceleration for the fifth radius; 10.0 m