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3 years ago

Find the value of x for which r || S. A) 44 B) 10 C) Can't be determined. D) 14

Mathematics

2 answers:

nlexa [21]3 years ago

5 0

The answer is A because 10 and 14 don’t fit the question at all.

Elodia [21]3 years ago

4 0

Answer:

x=44

Step-by-step explanation:

For the two lines to be parallel, the two angles have to add to 180 degrees

45+3x+3 =180

Combine like terms

3x+48 = 180

Subtract 48 from each side

3x+48-48=180-48

3x=132

Divide each side by 3

3x/3 = 132/3

x =44

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The surface areas of two similar hexagonal prisms are 882cm² and 1,058 cm²? What is the scale factor of the smaller

max2010maxim [7]

Answer:

scale factor of the smaller prism to the larger prism is B. 21/23

Step-by-step explanation:

Given

surface areas of two similar hexagonal prisms are 882cm² and 1,058 cm²?

scale factor is ratio of sides of two similar objects

thus scale factor for given prism will be = side of smaller prism / side of larger prism

in general rule

If shape of solid has scale factor of k

scale factor of area = k²

scale factor of volume = k³

_____________________________

Given in the problem area of two prism is given

we know area = side^2

scale factor of area = k²

k^2 = area of smaller prism / area of larger prism

$k^2 = 882 / 1058 = 441/529\\k = \sqrt{ 441/529} \\k = 21/23$

Thus, correct option is B 21/23.

7 0

2 years ago

Find the value of b.<br> 15°<br> 25°<br> bº<br> b=

kvv77 [185]

Answer:

Step-by-step explanation:

15 plus 10 equals 25.

25 plus 10 equals 35.

Hope it helps!

7 0

3 years ago

Which property justifies this statement?

Katen [24]

I know its not division,addition,multiplication,with the process of elimination its reflexive

5 0

3 years ago

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I need help with this question and it is (In customary units, what would be the most appropriate unit of measure to find the len

Norma-Jean [14]

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2. Feet
3. Miles
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3 years ago

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Use Stokes' Theorem to evaluate C F · dr where C is oriented counterclockwise as viewed from above. F(x, y, z) = xyi + 5zj + 7yk

REY [17]

By Stokes' theorem,

$\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

where $S$ is the surface with $C$ as its boundary. The curl is

$\nabla\times\vec F(x,y,z)=2\,\vec\imath-x\,\vec k$

Parameterize $S$ by

$\vec\sigma(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath+(8-u\cos v)\,\vec k$

with $0\le u\le9$ and $0\le v\le2\pi$ . Then take the normal vector to $S$ to be

$\vec\sigma_u\times\vec\sigma_v=u\,\vec\imath+u\,\vec k$

Then the line integral is equal to the surface integral,

$\displaystyle\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S=\int_0^{2\pi}\int_0^9(2\,\vec\imath-u\cos v\,\vec k)\cdot(u\,\vec\imath+u\,\vec k)\,\mathrm du\,\mathrm dv$

$\displaystyle=\int_0^{2\pi}\int_0^9(2u-u^2\cos v)\,\mathrm du\,\mathrm dv=\boxed{162\pi}$

7 0

2 years ago