Answer:
-6/-2<-2x/-2
divide both sides by-2 to remain with the x variable on one side
I hope this helps
Answer:
36
Step-by-step explanation:
Answer:
128.8 cm²
Step-by-step explanation:
In the image attached below, the regular polygon is a square which is composed of a small square and a large square. In a square, all the sides are equal.
For the small square, half of the diagonal is 4 cm, therefore the length of the diagonal is 8 cm (2 × 4 cm). Let the length of the side be a cm, using Pythagoras theorem:
a² + a² = 8²
2a² = 64
a² = 32
a = √32 = 5.7 cm
The area of the small square = length × length = 5.7 × 5.7 = 32.5 cm²
For the large square, half of the diagonal is 9 cm, therefore the length of the diagonal is 18 cm (2 × 9 cm). Let the length of the side be b cm, using Pythagoras theorem:
b² + b² = 18²
2b² = 324
b² = 162
b = √162 = 12.7 cm
The area of the large square = length × length = 12.7 × 12.7 = 161.3 cm²
The area of the shaded region = Area of large square - Area of small square = 161.3 cm² - 32.5 cm² = 128.8 cm²
G(x)= d( d*x)= 0 is what i believe is your answer
Hello from MrBillDoesMath!
Answer:
6x^3 + x^2 -9x + 10
which is the first choice.
Discussion:
(3x + 5) ( 2x^2 - 3x +2 ) =
(3x)
( 2x^2 - 3x +2 ) + 5 ( 2x^2 - 3x +2 ) =
6x^3 - 9x^2 + 6x + 10x^2 - 15x + 10 =
6x^3 + x^2 -9x + 10
which is the first choice.
Thank you,
MrB