Answer:
c. y + 1 = -⅕(x - 2)
Step-by-step explanation:
To write the equation in point-slope form, we need to know the slope (m) and coordinates of a point the line passes through.
The equation would be in the form of y - b = m(x - a).
(a, b) = (2, -1)
Since the line is perpendicular to y = 5x + 3, the slope will be the negative reciprocal of 5 which is -⅕
m = -⅕.
Substitute a = 2, b = -1, and m = -⅕ into y - b = m(x - a).
Thus:
y - (-1) = -⅕(x - 2)
y + 1 = -⅕(x - 2)
Well first you have to add common like terms in this case 2r and -6r to get -4r now your equation is -4r+8=40, now subtract 8 from both sides to leave r by itself and get -4r=32, now divide both sides by -4 to get r=-8
Hope this helps
Answer: 21
Step-by-step explanation: 84/4 = 21
Evaluate (2 a + b)^2/(3 b - 1) where a = -2 and b = 5:
(2 a + b)^2/(3 b - 1) = (5 - 2×2)^2/(3×5 - 1)
3×5 = 15:
(5 - 2×2)^2/(15 - 1)
| 1 | 5
- | | 1
| 1 | 4:
(5 - 2×2)^2/14
2 (-2) = -4:
(-4 + 5)^2/14
5 - 4 = 1:
1^2/14
1^2 = 1:
Answer: 1/14
