Answer:
The interval of increase of g(x) is
.
Step-by-step explanation:
The interval of increase occurs when first derivative of given function brings positive values. Let be
, the first derivative of the function is:


The following condition must be met to define the interval of increase:

The first term is always position due to the quadratic form, the second one is a first order polynomial and it is known that positive value is a product of two positive or negative values. Then, the second form must satisfy this:

The solution to this inequation is:

Now, the solution to this expression in interval notation is: 
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Yearly would get you $8316
Hope this helps
28 + vector b = -12
vector b = -40
vector b has magnitude 40 units in the negative y direction.
It should be 12×18. 1:3 means you take where it's at, at 1 and multiply it's size by 3.