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MrMuchimi
3 years ago
15

Heather wants to enlarge a 4 x 6 in picture using a scale factor of 1:3. What will be the dimensions of the picture after she en

larges it?
Mathematics
2 answers:
Kitty [74]3 years ago
8 0
<h2>Answer:</h2>

The  dimensions of the picture after she enlarges it is:

                              12×18

<h2>Step-by-step explanation:</h2>

It is given that:

Heather wants to enlarge a 4 x 6 in picture using a scale factor of 1:3.

This means that the dimension of the enlarged picture will be three times the dimensions of the original picture.

i.e. one of the side will be: 4×3=12

and the other side will be: 6×3=18

Hence, the dimensions are: 12×18

salantis [7]3 years ago
5 0
It should be 12×18. 1:3 means you take where it's at, at 1 and multiply it's size by 3.
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Using the domain, it is found that x = -8 is excluded for the product.

The domain of a function is the <u>set that contains all possible input values</u>.

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In this problem, there are two fractions, and the points outside the domain, that is, the roots of the denominators, are excluded.

For the first fraction, they are:

3x^2 + 6x = 0

3x(x + 2) = 0

3x = 0 \rightarrow x = 0

x + 2 = 0 \rightarrow x = -2

Hence, x = -2(not an option) is excluded.

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For the second fraction, the roots of the denominator are:

x^2 + 11x + 24 = 0

Which is a quadratic equation with <u>coefficients</u> a = 1, b = 11, c = 24, hence:

\Delta = b^2 - 4ac = 11^2 - 4(1)(24) = 121 - 96 = 25

x_1 = \frac{-b - \sqrt{\Delta}}{2a} = \frac{-11 - 5}{2} = -8

x_2 = \frac{-b + \sqrt{\Delta}}{2a} = \frac{-11 + 5}{2} = -3

x = -3 can be factored with the numerator of the first fraction, so only x = -8 is excluded.

A similar problem is given at brainly.com/question/13136492

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Step-by-step explanation:

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For C I did this:

Divided the denominators: 28 ÷ 20 = 1.4....so that's 1.4.

Let's test it out for the numerator now. 21 ÷ 15 = 1.4.

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4 years ago
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Answer:

A. P = 72 feet, A = 300 square feet

Step-by-step explanation:

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