Answer:
B. 21.2
Step-by-step explanation:
Perimeter of ∆ABC = AB + BC + AC
A(-4, 1)
B(-2, 3)
C(3, -4)
✔️Distance between A(-4, 1) and B(-2, 3):
AB = 4 units
✔️Distance between B(-2, 3) and C(3, -4):
BC = 8.6 units (nearest tenth)
✔️Distance between A(-4, 1) and C(3, -4):
AC = 8.6 units (nearest tenth)
Perimeter of ∆ABC = 4 + 8.6 + 8.6 = 21.2 units
F(x)=4X X=5
F(5)=4X
4(5)
20
Y=4(20)
Y=80