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3 years ago

5

The owner of a dress shop orders 33 dresses. The dresses now make up 30% of all dresses in the shop. How many dresses are in the

shop?

1 answer:

velikii [3]3 years ago

6 0

dresses *.30 = 33

divide by .30

dresses =110

There are 110 dresses in the shop

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All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be

Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a student is proficient in reading but not mathematics and $A \cap B$ is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

$B = b + (A \cap B)$

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

$(A \cup B) + C = 1$

In which

$(A \cup B) = a + b + (A \cap B)$

65% were found to be proficient in both reading and mathematics.

This means that $A \cap B = 0.65$

78% were found to be proficient in mathematics

This means that $B = 0.78$

$B = b + (A \cap B)$

$0.78 = b + 0.65$

$b = 0.13$

85% of the students were found to be proficient in reading

This means that $A = 0.85$

$A = a + (A \cap B)$

$0.85 = a + 0.65$

$a = 0.20$

Proficient in at least one:

$(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98$

What is the probability that the student is proficient in neither reading nor mathematics?

$(A \cup B) + C = 1$

$C = 1 - (A \cup B) = 1 - 0.98 = 0.02$

There is a 2% probability that the student is proficient in neither reading nor mathematics.

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3 years ago

What is the solution to the compound inequality 3x-8>-5 and 2x-7<5

-BARSIC- [3]

Answer:

<h2>1 < x < 6 ⇒ x ∈ (1, 6)</h2>

Step-by-step explanation:

3x - 8 > -5 <em>add 8 to both sides</em>

3x > 3 <em>divide both sides by 3</em>

x > 1

2x - 7 < 5 <em>add 7 to both sides</em>

2x < 12 <em>divide both sides by 2</em>

x < 6

From x > 1 and x < 6 we have the solution 1 < x < 6 ⇒ x ∈ (1, 6)

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3 years ago

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Arada [10]

I think it’s d. A percent is out of 100 so it’s 156/100

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3 years ago

Use the graph below to determine a1 and d for the sequence. graphed sequence showing point 1, negative 10, point 2, negative 7,

Sonja [21]

Answer:

$a_1=-10$

$d=3$

Step-by-step explanation:

we know that

In an <u><em>Arithmetic Sequence</em></u> the difference between one term and the next is a constant, and this constant is called the common difference (d)

In this problem we have the ordered pairs

$(1,-10),(2,-7),(3,-4),(4,-1),(5,2),(6,5)$

Let

$a_1=-10\\a_2=-7\\a_3=-4\\a_4=-1\\a_5=2\\a_6=5$

Find the difference between one term and the next

$a_2-a_1=-7-(-10)=3$

$a_3-a_2=-4-(-7)=3$

$a_4-a_3=-1-(-4)=3$

$a_5-a_4=2-(-1)=3$

$a_6-a_5=5-2=3$

The difference between one term and the next is a constant

This constant is the common difference

so

The sequence graphed is an Arithmetic Sequence

therefore

The first term is $a_1=-10$

The common difference is equal to $d=3$

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3 years ago

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SashulF [63]

Answer:

the third one

Step-by-step explanation:

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4 years ago

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