Answer: 0.03125
Step-by-step explanation:
We know that the probability of getting a tail , we toss a fair coin = 0.5
Given : Total number of trials = 5
Using binomial probability formula :
, where P(x) is the probability of getting success in x trails, n is total number of trials and p is the probability of getting success in each trial.
The probability of getting "tails" on all five coins :_
Hence, the probability of getting "tails" on all five coins =0.03125
The solution to the problem is as follows:
If you use Ln you can get rid of e.
ln(e^0.4x) = ln(0.4)
0.4x = ln(0.4)
x = (ln(0.4))/0.4
<span>x = -2.29
</span>
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Answer:
a 10 yd 2ft 7 in
b 10 yd 1 ft 2 in
c 99 yd
d. 4840 sq yd 7 sq ft 119 sq in
Step-by-step explanation:
a. 2 ft. 5 in. +
9 yd. 3 ft. 2 in.
---------------------
9 yd 5ft 7 in
but 3 ft = 1yd
9 yd 5ft 7 in
+1yd - 3ft
---------------------------
10 yd 2ft 7 in
b. 4 yd. 8 in
+ 6 yd. 6 in.
----------------------
10 yd 14 in
but 12 in = 1ft
10 yd 14 in
+ 1ft - 12 in
---------------------
10 yd 1 ft 2 in
c. 29 yd. 2 ft. 11 in.
55 yd. 1 ft. 10 in.
+ 13 yd. 1 ft. 3 in.
--------------------------
97 yd 4 ft 24 in
12 in = 1ft
24 in = 2ft
97 yd 4 ft 24 in
+2ft - 24 in
--------------------------------
97 yd 6ft
3 ft = 1yd
6f = 2yd
97 yd 6ft
+2yd - 6ft
---------------------
99 yd
d. 4,839 sq. yd. 8 sq. ft. 139 sq. in.
+ 7 sq. ft. 124 sq. in.
--------------------------------------------------
4839 sq yd 15 sq ft 263 sq in
12*12 = 144 sq in = 1 sq ft
4839 sq yd 15 sq ft 263 sq in
+ 1 sq ft - 144 sq in
--------------------------------------------------
4839 sq yd 16 sq ft 119 sq in
3ft * 3 ft = 9 sq ft = 1 sq yd
4839 sq yd 16 sq ft 119 sq in
+1 sq yd - 9 sq ft
----------------------------------------------
4840 sq yd 7 sq ft 119 sq in
Answer:
That is a variable.
Step-by-step explanation:
- opposed to a constant which is known and does not change.
Answer:
8 hours 48 mins
Step-by-step explanation:
h m
5:15
+3:33
--------------
8:48
or
5 hours + 3 hours =8 hours,
15 mins + 33 mins = 48 mins
Therefore, it's 8 hours 48 mins.
