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4 years ago

What is the importance of the electrons? (write in one paragraph)

2 answers:

6 0

Well in everything we have protons and electrons, eg. In static electricity in a balloon when you rub the balloon on a material like your hair all the protons come off and into your hair which makes your hair go upright and funny and the balloon is desperate to get back the protons so it sticks to surfaces to gain there protons to balance out the electrons it already has for it to be neutral again. Because it's important for everything that can be to be neutral

My name is Ann [436]4 years ago

4 0

Well in everything we have protons and electrons, eg. In static electrisity in a balloon when you rub the balloon on a material like your hair all the protons come off and into your hair which makes your hair go upright and funny and the ballon is desperate to get back the protons so it sticks to surfaces to gain there protons to ballance out the electrons it allready has for it to be nuteral again. Because its important for everything that can be to be nuteral

You might be interested in

Why is the mixture of the titration of potassium permanganate solution using oxalic acid heated before titration?

alexgriva [62]

Explanation:

During titration of oxalic acid and $KMnO_4$ in acid medium to reaction is extremely slow. Since $KMnO_4$ is acting as a self indicator the colour disappears after less than 30s even after approaching equivalent point. So the reaction mixture is heated to approximately 70– $80^0 C$ (just before it starts boiling) and the titration is started. This helps in initiating the reaction via supplying the necessary activation energy of the reaction. Secondly the heat helps to decompose $[Mn(C_2O_4)^3]^{-3}$ complex which forms as a result of local excess of $KMnO_4$ .the complex is unstable above $60^0C$ and the $Mn^{+2}$ formed as a result catalyses the rest of the reaction. Thirdly the temp should never exceed the range given as oxalic acid will decompose above this temp to $Co_2$

4 0

4 years ago

Read 2 more answers

For the reaction:

Zepler [3.9K]

Answer:

The equilibrium constant for CO now

= 0.212 M

For H₂O

= 0.212 M

For CO₂ = x = 0.2880 M

For H₂ = x = 0.2880 M

Explanation:

The chemical equation for the reaction is:

CO(g) + H2O(g) ⇌ CO2(g) + H2(g)

The ICE Table for this reaction can be represented as follows:

CO(g) + H2O(g) ⇌ CO2(g) + H2(g)

Initial 0.5 0.5 - -

Change -x -x + x + x

Equilibrium 0.5 -x 0.5 - x

The equilibrium constant $K_c = \dfrac{[x][x]}{[0.5-x][0.5-x]}$

$K_c = \dfrac{[x]^2}{[0.5-x]^2}$

where; $K_c = 1.845$

$1.845 = \begin {pmatrix} \dfrac{x}{0.5-x} \end {pmatrix}^2$

$\sqrt{1.845}= \begin {pmatrix} \dfrac{x}{0.5-x} \end {pmatrix}$

$1.3583= \begin {pmatrix} \dfrac{x}{0.5-x} \end {pmatrix}$

1.3583 (0.5-x) = x

0.67915 - 1.3583x = x

0.67915 = x + 1.3583x

0.67915 = 2.3583x

x = 0.67915/2.3583

x = 0.2880

The equilibrium constant for CO now = 0.5 - x

= 0.5 - 0.2880

= 0.212 M

For H₂O = 0.5 - x

= 0.5 - 0.2880

= 0.212 M

For CO₂ = x = 0.2880 M

For H₂ = x = 0.2880 M

3 0

3 years ago

What is the mass of 1.58 moles of CH4

HACTEHA [7]

<h3>Answer:</h3>

25.4 g CH₄

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

1.58 mol CH₄

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of C - 12.01 g/mol

[PT] Molar Mass of H - 1.01 g/mol

Molar Mass of CH₄ - 12.01 + 4(1.01) = 16.05 g/mol

<u>Step 3: Convert</u>

Set up: $\displaystyle 1.58 \ mol \ CH_4(\frac{16.05 \ g \ CH_4}{1 \ mol \ CH_4})$
Multiply/Divide: $\displaystyle 25.359 \ g \ CH_4$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

25.359 g CH₄ ≈ 25.4 g CH₄

4 0

3 years ago

To pull up a bucket of water from a well, George pulled hard on a handle to wind up a rope. Which kind of energy was George appl

mote1985 [20]

b frictional energy

is the correct answer

4 0

3 years ago

Compound A, C6H12 reacts with HBr/ROOR to give compound B, C6H13Br. Compound C, C6H14, reacts with bromine and light to produce

Savatey [412]

Answer:

The question involves drawing of structures and showing mechanism in which brainly text editor did not support. I made sure I created a pdf file with both the anwsers and explanations in it. The pdf can be found in the attachment below.

Explanation:

Download pdf

3 0

3 years ago