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artcher [175]
4 years ago
15

A. Use the following data to calculate the enthalpy of hydration for calcium chloride and calcium iodide.

Chemistry
1 answer:
siniylev [52]4 years ago
4 0

Answer:

A. Enthalpy of hydration of CaCl2 = -2293 KJ/mol

Enthalpy of hydration of CaI2 = -2163 KJ/mol

B. Chloride ions

Explanation:

Enthalpy of hydration is the energy required to convert one mole of gaseous ions to aqueousions.

Enthalpy of hydration = Enthalpy of solution - lattice energy

For CaCl2;

Enthalpy of hydration = -46 - 2247 = -2293 KJ/mol

For CaI2;

Enthalpy of hydration = -104 - 2059 = -2163 KJ/mol

B. Since the enthalpy of hydration of CaCl2 is more negative than that of CaI2, it means that chloride ions are more easily attracted to water molecules. This we conclude because the difference in enthalpy values are due to the negative ions as the two compounds share a common positive calcium ion.

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How many moles of gas would occupy a 25.0 liter when the temp is 22.0 degrees celsius and the pressure is 646 torr
Luda [366]

Answer:

0.877 mol  

Step-by-step explanation:

We can use the<em> Ideal Gas Law </em>to solve this problem.

pV = nRT     Divide both sides by RT

 n = (pV)/(RT)

Data:

p = 646 torr

V = 25.0 L

R = 0.082 06 L·atm·K⁻¹mol⁻¹

T = 22.0 °C

Calculations:

(a) <em>Convert the pressure to atmospheres </em>

p = 646 torr × (1 atm/760 torr) = 0.8500 atm

(b) <em>Convert the temperature to kelvins </em>

T = (22.0 + 273.15) K = 295.15 K

(c) <em>Calculate the number of moles </em>

n = (0.8500 × 25.0)/(0.082 06 × 295.15)

  = 0.877 mol

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3 years ago
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4 years ago
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LiOH + KCI → LiCl + KOH
yulyashka [42]

Answer:

35.42g

Explanation:

LiOH + KCI → LiCl + KOH

Let us determine the molar mass of LiOH and LiCl. This is illustrated below:

Molar Mass of LiOH = 7 + 16 + 1 = 24g/mol

Molar Mass of LiCl = 7 + 35.5 = 42.5g/mol.

Now, we can obtain the theoretical yield of LiCl as follow:

From the equation above,

24g of LiOH reacted to produce 42.5g of LiCl.

Therefore, 20g of LiOH will react to produce = (20 x 42.5)/24 = 35.42g of LiCl.

From the above calculations, the theoretical yield of LiCl is 35.42g

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4 years ago
Calculate the density of a solid in g/cm3 if it weighs 38.3 kg and has a volume of 0.00463 m3.
RideAnS [48]

Answer: D=8.27 g/cm³

Explanation:

Density is mass/volume. Mass is in grams and volume is in liters. In this case, the problem wants our volume to be in cm³. All we need to do is to make some conversions to convert kg/m³ to g/cm³.

D=\frac{38.3kg}{0.00463m^3} *\frac{(1m)^3}{(100cm)^3} *\frac{1000g}{1kg}

With this equation, the m³ and kg cancel out, and we are left with g/cm³.

D=8.27 g/cm³

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3 years ago
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