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Snezhnost [94]
2 years ago
9

PLEASE HELP ASAP!!

Chemistry
2 answers:
weqwewe [10]2 years ago
4 0

B) the dependent variable relies upon the independent variable

nikitadnepr [17]2 years ago
3 0

The answer is B) The dependent variable relies upon the independent variable

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A 5.00 L flask contains 7.94 g of a gas at STP. What is the molar mass of the gas?​
Rashid [163]

Answer: 35.6 g/mol

Explanation: I guessed and got it correct

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2 years ago
Sodium chloride (NaCl) is an ionic solid. It dissolves easily in water. Which property of water allows it to dissolve NaCl?
WINSTONCH [101]
Its hydrogen atom is a high conductor of electricity
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2 years ago
What dose buoyancy have to do with jumping?
Naddika [18.5K]
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8 0
3 years ago
The specific reaction rate of a reaction at 492k is 2.46 second inverse and at 528k 47.5 second inverse.find activation energy a
crimeas [40]

Answer:

Ea = 177x10³ J/mol

ko = 1.52x10^{19} J/mol

Explanation:

The specific reaction rate can be calculated by Arrhenius equation:

k = koxe^{-Ea/RT}

Where k0 is a constant, Ea is the activation energy, R is the gas constant, and T the temperature in Kelvin.

k depends on the temperature, so, we can divide the k of two different temperatures:

\frac{k1}{k2} = \frac{koxe^{-Ea/RT1}}{koxe^{-Ea/RT2}}

\frac{k1}{k2} = e^{-Ea/RT1 + Ea/RT2}

Applying natural logathim in both sides of the equations:

ln(k1/k2) = Ea/RT2 - Ea/RT1

ln(k1/k2) = (Ea/R)x(1/T2 - 1/T1)

R = 8.314 J/mol.K

ln(2.46/47.5) = (Ea/8.314)x(1/528 - 1/492)

ln(0.052) = (Ea/8.314)x(-1.38x10^{-4}

-1.67x10^{-5}xEa = -2.95

Ea = 177x10³ J/mol

To find ko, we just need to substitute Ea in one of the specific reaction rate equation:

k1 = koxe^{-Ea/RT1}

2.46 = koxe^{-177x10^3/8.314x492}

1.61x10^{-19}ko = 2.46

ko = 1.52x10^{19} J/mol

3 0
3 years ago
One statement of the first law of thermodynamics is that
Phantasy [73]
The First Law of Thermodynamics states that heat is a form of energy, and thermodynamic processes are therefore subject to the principle of conservation of energy. This means that heat energy cannot be created or destroyed.
7 0
3 years ago
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