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3 years ago

How to solve this kind of question? Show steps!

Mathematics

1 answer:

melomori [17]3 years ago

7 0

350 dollars for the kayak + 1.50 for the fee + the 10.23 interest for the three months = 361.73

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Multiply the binomials using the method foil (5x+1)(x+2)

zepelin [54]

The answer is $5x^{2} \\$ + $11x$ + $2$

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3 years ago

CS Algebra

CaHeK987 [17]

Answer:

Hope this helps :)

Step-by-step explanation:

8(x - 2) = 2x + 8

y+9 = -2(y + 1)

value of x in 8(x - 2) = 2x + 8

x=4

substitue

y+9=−2(y+1)

value of y y+9=−2(y+1)

y= - 11/3 or 3.66...

x=4

y=4 (I rounded 3.66)

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2 years ago

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Tpy6a [65]

Sin is x
tan is y

Hope this helped☺☺

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2 years ago

Find the volume of the following solid. The solid between the cylinder f(x,y)equals=e Superscript negative xe−x and the region

PilotLPTM [1.2K]

It is hard to comprehend your question. As far as I understand:

f(x,y) = e^(-x)

Find the volume over region R = {(x,y): 0<=x<=ln(6), -6<=y <= 6}.

That is all I understood. It would be easier to understand with a picture or some kind of visual aid.

Anyways, to find the volume between the surface and your rectangular region R, we must evaluate a double integral of f on the region R.

$\iint_{R}^{ } e^{-x}dA=\int_{-6}^{6} \int_{0}^{ln(6)} e^{-x}dx dy$

Now evaluate,

$\int_{0}^{ln(6)}e^{-x}dx$

which evaluates to, 5/6 if I did the math correct. Correct me if I am wrong.

Now integrate this w.r.t. y:

$\int_{-6}^{6}\frac{5}{6}dy = 10$

So,

$\iint_{R}^{ } e^{-x}dA=\int_{-6}^{6} \int_{0}^{ln(6)} e^{-x}dx dy = 10$

7 0

2 years ago

What is the volume of a cylinder with the base radius of 10 units and a height of nine units?

Otrada [13]

Answer:

$V = 2827.43\ units^3$ or $V = 900\pi\ units^3$

Step-by-step explanation:

The volume of a cylinder is calculated by the following formula

$V = \pi r^2 *h$

Where r is the radius of the cylinder and h is the height

In this case we know that the radius r of the base is:

$r=10\ units$

and

$h=9\ units$

So the Volume is:

$V = \pi (10)^2 *9$

$V = 900\pi\ units^3$

$V = 2827.43\ units^3$

7 0

3 years ago

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