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3 years ago

Nail this puzzle down

Mathematics

2 answers:

k0ka [10]3 years ago

7 0

What puzzle did you mean by?

adoni [48]3 years ago

5 0

Answer:

what puzzle? lol

Step-by-step explanation: yep your welcome

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5300 divided by 10 to the third power

BabaBlast [244]

5.3 is answer to problem

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3 years ago

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A certain vibrating system satisfies the equation . Find the value of the damping coefficient for which the quasi period of the

Likurg_2 [28]

Answer:

Hence the value of damping coefficient = 1.49071.

Step-by-step explanation:

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3 years ago

Evaluate M^2 /p^2 for M = 10, N =-5p and P = -2

kondaur [170]

<u>Answer: </u>

The solution of $\bold{\frac{M^{2}}{P^{2}}}$ for M = 10, N = -5P and P = -2 is 25

<u>Solution: </u>

From question, given that the value of M is 10 and N is -5p and P is -2

We have to evaluate the value of $\frac{M^{2}}{P^{2}}$ ,

By substituting the values of M and N, we get

$\frac{M^{2}}{P^{2}} = \frac{10^{2}}{(-2)^{2}}$

Expanding $\bold{10^{2}}$ :

Here 10 is the base value and 2 is the exponent value. So the base term 10 is multiplied by itself two times.

$10^{2} = 10 \times 10 = 100$

Similarly expanding $\bold{(-2)^{2}}$ :

Here -2 is the base term and 2 is the exponent value. So the base term -2 is multiplied by itself two times.

$(-2)^{2} = -2 \times -2 = 4$

So the equation $\frac{M^{2}}{P^{2}} = \frac{10^{2}}{(-2)^{2}}$ becomes,

$\frac{M^{2}}{P^{2}} = \frac{100}{4}$

By dividing 100 by 4 , we get the result as 25

Hence the solution of $\bold{\frac{M^{2}}{P^{2}}}$ when M = 10 and P = -2 is 25

6 0

3 years ago

What is 3×10^3-7000/(8×(-5))+4^2+2^2) in simplest form

guapka [62]

-4000 is the answer, I believe

3 0

3 years ago

A 24-centimeter by 119-centimeter piece of cardboard is used to make an open-top box by removing a square from each corner of th

satela [25.4K]

Answer:

The size square removed from each corner = 32.15 cm²

Step-by-step explanation:

The volume of the box = Length * Breadth * Height

Let r be the size removed from each corner

Note that at maximum volume, $\frac{dV}{dr} = 0$

The original length of the cardboard is 119 cm, if you remove a size of r (This typically will be the height of the box) from the corner, since there are two corners corresponding to the length of the box, the length of the box will be:

Length, L = 119 - 2r

Similarly for the breadth, B = 24 - 2r

And the height as stated earlier, H = r

Volume, V = L*B*H

V = (119-2r)(24-2r)r

V = r(2856 - 238r - 48r + 4r²)

V = 4r³ - 286r² + 2856r

At maximum volume dV/dr = 0

dV/dr = 12r² - 572r + 2856

12r² - 572r + 2856 = 0

By solving the quadratic equation above for the value of r:

r = 5.67 or 42

r cannot be 42 because the size removed from the corner of the cardboard cannot be more than the width of the cardboard.

Note that the area of a square is r²

Therefore, the size square removed from each corner = 5.67² = 32.15 cm²

5 0

3 years ago