All categories

2 years ago

How long will it take a person to walk from Toronto to

Mathematics

1 answer:

storchak [24]2 years ago

4 0

Answer:

About 947 hours, walking at 5 km (3 miles)/hour.

Walking 8 hours /day [at that pace you would need to be an Olympic Athlete to keep up the pace] it will take about four months.

Walk slower, it will take longer.

You might be interested in

Which value represents the correlation coefficient for this data

AfilCa [17]

Its 0.20 i think bc its the one that make the most since

3 0

3 years ago

Which of the following sets is NOT closed under addition.

Veronika [31]

Answer:

Step-by-step explanation:

The odd numbers.

Suppose you have 31 and 27 when you add these two together, you get 58 which is not an odd number.

If you need a more mathematical proof, you could do it this way.

2x+1

2x is even. Anything multiplied by 2 is even. When you add 1 you get an odd number

So continue on

2y + 1 is the other number.

2x + 1 + 2y + 1 = 2(x + y) + 2

2 (x + y ) is even. When you add 2 to it, nothing changes. The result is still even.

7 0

3 years ago

If f(x) = 2x^4, then f'(3) =

valkas [14]

To find f'(3) (f prime of 3), you must find f' first. f' is the derivative of the function f(x).

Finding the derivative of f(x) = 2x⁴ requires the use of the power rule.

The power rule for derivatives is $\frac{d}{dx} [x^{n} ] =nx^{n-1}$ . In other words, you bring the exponent forward and multiply it by the coefficient of the term, and then you subtract 1 from the original exponent.

f'(x) = $\frac{d}{dx}$ (2x⁴)

f'(x) = 2(4)x³

f'(x) = 8x³

Now, to find f'(3), plug 3 into your derivative.

f'(3) = 8(3)³

f'(3) = 216

<h3>Answer:</h3>

f'(3) = 216

6 0

3 years ago

Which set of graphs can be used to find the solution set to 3e* > >-x?

kobusy [5.1K]

The attached graph represents the solution set of $3e^x > \frac 12^x$

<h3>How to determine the graph?</h3>

The complete options are not given.

So, I would plot the graph that represents the solution set

The inequality is given as:

$3e^x > \frac 12^x$

Start by splitting the inequalities as follows:

$f(x) > 3e^x$

$g(x) > \frac 12^x$

The above means that we plot the graphs of f(x) and g(x) to represent the solution set

See attachment