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sashaice [31]
3 years ago
8

I need help with the answer and also the formula you used to find the answer

Mathematics
1 answer:
Blababa [14]3 years ago
6 0

Answer:

i think its b i could be wrong if i am im so sorry

Step-by-step explanation:

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HELP!! I WILL GIVE BRAINLIEST
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Number one: Just plot down on the number like the numbers you have. Just took the test for this.

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3 years ago
Express the volume of the box as a<br>polynomial in the variable x
Whitepunk [10]

The volume of the box as a polynomial in the variable x is x(12 - 2x)(7 - 2x)

<h3>How to determine the volume?</h3>

The complete question is added as an attachment

From the attached image, we have:

Length = 12 - 2x

Width = 7 - 2x

Height = x

The volume is calculated as:

Volume = Length * Width * Height

Substitute the known values in the above equation

Volume = (12 - 2x) * (7 - 2x) * x

This gives

Volume = x(12 - 2x)(7 - 2x)

Hence, the volume of the box as a polynomial in the variable x is x(12 - 2x)(7 - 2x)

Read more about polynomial at:

brainly.com/question/4142886

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7 0
2 years ago
A marketing company is hiring two college students to hand out brochures near an event.Marshall hands out 300 brochures in 2 hou
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B.Silas because she did more in less time he handed out 300 but in 2 hours and she handed out 240 in 90 minutes she handed out more brochures


6 0
3 years ago
Read 2 more answers
Determine the values of xfor which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001.(Enter
MrMuchimi

Answer:

The values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001 is 0 < x < 0.3936.

Step-by-step explanation:

Note: This question is not complete. The complete question is therefore provided before answering the question as follows:

Determine the values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001. f(x) = e^x ≈ 1 + x + x²/2! + x³/3!, x < 0

The explanation of the answer is now provided as follows:

Given:

f(x) = e^x ≈ 1 + x + x²/2! + x³/3!, x < 0 …………….. (1)

R_{3} = (x) = (e^z /4!)x^4

Since the aim is R_{3}(x) < 0.001, this implies that:

(e^z /4!)x^4 < 0.0001 ………………………………….. (2)

Multiply both sided of equation (2) by (1), we have:

e^4x^4 < 0.024 ……………………….......……………. (4)

Taking 4th root of both sided of equation (4), we have:

|xe^(z/4) < 0.3936 ……………………..........…………(5)

Dividing both sides of equation (5) by e^(z/4) gives us:

|x| < 0.3936 / e^(z/4) ……………….................…… (6)

In equation (6), when z > 0, e^(z/4) > 1. Therefore, we have:

|x| < 0.3936 -----> 0 < x < 0.3936

Therefore, the values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001 is 0 < x < 0.3936.

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3 years ago
Find the area of the polygon.<br> 2 cm<br> 3 cm<br> 1 cm<br> 3 cm<br> 4 cm
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Answer:

the area of the problem is 20

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