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3 years ago

Which of these graphs shows a relationship that is NOT proportional? (PLEASEEE HELP)

Mathematics

1 answer:

Lilit [14]3 years ago

8 0

Answer:

Step-by-step explanation:

it doesnt

run through the origin

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Which figure could be the result of dilating this triangle with a scale factor greater than 1? On a coordinate plane, a triangle

Ierofanga [76]

Answer:

3rd answer choice

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Elise and her dad are planning to attend the state fair. An adult ticket is $21.00. The price of an adult ticket is $10.00 more

solong [7]

Answer:

C. two thirds x + 10 = 21

Step-by-step explanation:

Given

Price of adult ticket = $21.00

Let x be the price of student ticket

Then

two third of the student ticket will be:

$\frac{2}{3} x$

The statement $10.00 more than two third of student ticket:

$\frac{2}{3} x+10$

As we are given in the question that the adult ticket price is $21.00 and the second explanation is th equation formed by the given statement

So, both will be equivalent

$\frac{2}{3} x+10 = 21$

Solving this equation for x will give us the price for the student ticket.

Hence,

C. two thirdsx + 10 = 21 is the correct answer ..

3 0

3 years ago

Simplify<br><br>-5/7(-(1 1/3-3/4)+1/3 / 4

koban [17]

Answer:

=5/21L+ -5/84

Step-by-step explanation:

=-(5/7) (-(1L/3-3/4)+1/3/4)

=(-5/7)(-(1L/3-3/4))+(-5/7)(1/3/4)

=5/21L= -15/28+ -5/84

=5/21L=+ -25/42

7 0

3 years ago

. A right cylindrical drum is to hold 7.35 cubic feet of liquid. Find the dimensions (radius of the base and height) of the drum

Drupady [299]

Answer:

$r=1.05\ \text{ft}$

$h=2.12\ \text{ft}$

$20.91\ \text{ft}^3$

Step-by-step explanation:

r = Radius

h = Height

Volume of cylinder = $7.35\ \text{ft}^3$

$V=\pi r^2h\\\Rightarrow h=\dfrac{V}{\pi r^2}\\\Rightarrow h=\dfrac{7.35}{\pi r^2}$

Surface area is given by

$A=2\pi r^2+2\pi rh\\\Rightarrow A=2\pi r^2+2\pi r\dfrac{7.35}{\pi r^2}\\\Rightarrow A=2\pi r^2+\dfrac{14.7}{r}$

Differentiating with respect to radius we get

$\dfrac{dA}{dr}=4\pi r-\dfrac{14.7}{r^2}$

Equating with zero we get

$0=4\pi r-\dfrac{14.7}{r^2}\\\Rightarrow 4\pi r=\dfrac{14.7}{r^2}\\\Rightarrow r^3=\dfrac{14.7}{4\pi}\\\Rightarrow r=(\dfrac{14.7}{4\pi})^{\dfrac{1}{3}}\\\Rightarrow r=1.05$

$\dfrac{d^2A}{dr^2}=4\pi-2\times \dfrac{14.7}{r^3}\\\Rightarrow \dfrac{d^2A}{dr^2}=4\pi+2\times \dfrac{14.7}{1.05^3}\\\Rightarrow \dfrac{d^2A}{dr^2}=37.96>0$