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hoa [83]
3 years ago
7

Which of the following compounds is an Arrhenius base in water?

Chemistry
2 answers:
snow_lady [41]3 years ago
8 0
Arrhenius model considers a base a compound that produces OH(-)

H2SO4 produces H(+) and is an acid

C6H12O6 is an organic product, sugar, that does not produce OH(-)

HOClO2 = HClO3, which produces H(+) and is an acid

NH3 is believed to ionize in water and produce NH4(+) and OH(-).

As per this the answer is NH3.

Nevertheless, NH3 is not a good example of bases as per Arrhenius model, because it is not so evident that NH3 produces OH(-).
iogann1982 [59]3 years ago
3 0

Sodium hydroxide (NaOH) is an Arrhenius base, as NaOH is an ionic compound that dissociates into Na + and OH− ions when dissolved in water.

<h2>Further explanation </h2>

Acids and bases are two classes of chemicals that are very commonly found around us. For example, vinegar, citric acid, and acid in the stomach are classified as acid, while whiting and soda are classified as basic. Acids and bases have different properties. At first, acids and bases are distinguished by taste, where acids are sour while bases are bitter and slippery like soap. However, in general, acidic and basic substances are corrosive and toxic, especially in the form of high levels of the solution so that it is very dangerous if tested for its nature by the method of feeling it.

According to Arrhenius's theory, acids are defined as compounds that if dissociated in an aqueous solution liberate H + (hydrogen ions). A base is defined as a compound that dissociates in an aqueous solution liberating OH− (hydroxide ions).

Arrhenius Acid-Base Theory

This theory was first put forward in 1884 by Svante August Arrhenius. According to Arrhenius, the definitions of acids and bases, namely:

  • acid is a compound that dissolves in water releasing H + ions.
  • A base is a compound which, when dissolved in water, releases OH− ions.

Hydrochloric acid (HCl) which is very soluble in water is classified as Arrhenius acid, as HCl can decompose into H + and Cl− ions in water. Unlike the case with methane (CH4) which is not Arrhenius acid because it cannot produce H + ions in water even though it has H. Sodium hydroxide (NaOH) including Arrhenius bases, as NaOH is an ionic compound which dissociates into Na + and OH− ions when dissolved in water. The concept of Arrhenius acids and bases is limited to the condition of water as a solvent.

Learn more

acid and base theory brainly.com/question/2456608

Arrhenius theory brainly.com/question/2456608

Details

Class: high school

Subjects: Chemistry

Keywords: acids, bases, Arrhenius

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How many moles of iron can be made from 3 miles of Fe2O3
denis23 [38]

Answer: two moles

Explanation:

In one mole of fe2o3 there are two moles of iron atoms. Now gram atomic wt. of Fe is 56.So in one mole of Fe2O3 there are 2×56=112 gm of Fe. Hence in 1.75molesFe2O3 there are 1.75×2 moles or 1.75×56 gm of iron

8 0
3 years ago
Olympic cyclist fill their tires with helium to make them lighter. Calculate the mass of air in an air filled tire and the mass
inn [45]

<u>Answer:</u> The mass difference between the two is 7.38 grams.

<u>Explanation:</u>

To calculate the number of moles, we use the equation given by ideal gas follows:

PV=nRT

where,

P = pressure = 125 psi = 8.50 atm    (Conversion factor:  1 atm = 14.7 psi)

V = Volume = 855 mL = 0.855 L    (Conversion factor:  1 L = 1000 mL)

T = Temperature = 25^oC=[25+273]K=298K

R = Gas constant = 0.0821\text{ L. atm }mol^{-1}K^{-1}

n = number of moles = ?

Putting values in above equation, we get:

8.50atm\times 0.855L=n\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 298K\\\\n=\frac{8.50\times 0.855}{0.0821\times 298}=0.297mol

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For air:</u>

Moles of air = 0.297 moles

Average molar mass of air = 28.8 g/mol

Putting values in equation 1, we get:

0.297mol=\frac{\text{Mass of air}}{28.8g/mol}\\\\\text{Mass of air}=(0.297mol\times 28.8g/mol)=8.56g

Mass of air, m_1 = 8.56 g

  • <u>For helium gas:</u>

Moles of helium = 0.297 moles

Molar mass of helium = 4 g/mol

Putting values in equation 1, we get:

0.297mol=\frac{\text{Mass of helium}}{4g/mol}\\\\\text{Mass of helium}=(0.297mol\times 4g/mol)=1.18g

Mass of helium, m_2 = 1.18 g

Calculating the mass difference between the two:

\Delta m=m_1-m_2

\Delta m=(8.56-1.18)g=7.38g

Hence, the mass difference between the two is 7.38 grams.

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How mant liters at STP are in 0.575 moles of Kr​
gizmo_the_mogwai [7]

Answer:

12.9 L Kr

General Formulas and Concepts:

<u>Chemistry - Gas Laws</u>

  • Using Dimensional Analysis
  • STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

Explanation:

<u>Step 1: Define</u>

0.575 mol Kr

<u>Step 2: Identify Conversions</u>

1 mol= 22.4 L at STP

<u>Step 3: Convert</u>

<u />0.575 \ mol \ Kr(\frac{22.4 \ L \ Kr}{1 \ mol \ Kr} ) = 12.88 L Kr

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

12.88 L Kr ≈ 12.9 L Kr

8 0
3 years ago
Questions
Ulleksa [173]

Answers:

See below  

Step-by-step explanation:

1. Most food energy

(a) Pringles

Heat from Pringles + heat absorbed by water = 0

m₁ΔH  + m₂CΔT = 0

1.984ΔH + 100 × 4.184 × 18 = 0

1.984ΔH + 7530 = 0

ΔH = -7530/1.984 = -3800 J/g

(b) Cheetos

0.884ΔH + 418.4 × 13 = 0

ΔH = -5400/0.884 = -6200 J/g

Cheetos give you more food energy per gram.

(c) Snickers

Food energy = 215 Cal/28 g × 4184 J/1 Cal = 32 000 J/g

The food energy from Cheetos is much less than that from a Snickers bar

2. Experimental uncertainty

The experimental values are almost certainly too low.

Your burning food is heating up the air around it, so much of the heat of combustion is lost to the atmosphere.

3. Percent efficiency

Experimental food energy = 3800 J/g

Actual food energy = 150 Cal/28 g × 4184 J/1 Cal = 22 000 J/g

% Efficiency = Experimental value/Actual value × 100 %

                    = 3800/22 000 × 100 %

                    = 17 %

6 0
3 years ago
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