Answer:
13 is the distance
Step-by-step explanation:
Answer:
first one
Step-by-step explanation:
trust me im doing these too
<h2>
a. What is your equation?</h2>
This is a problem of projectile motion. A projectile is an object you throw with an initial velocity and whose trajectory is determined by the effect of gravitational acceleration. The general equation in this case is described as:
Where:
So:
Finally, the equation is:
<h2>b. How long will it take the rocket to reach its maximum height?</h2>
The rocket will reach the maximum height at the vertex of the parabola described by the equation 
. Therefore, our goal is to find 
at this point. In math, a parabola is described by the quadratic function:
So the x-coordinate of the vertex can be calculated as:
From our equation:
So:
So the rocket will take its maximum value after 1.99 seconds.
<h2>
c. What is the maximum height the rocket will reach?</h2>
From the previous solution, we know that after 1.99 seconds, the rocket will reach its maximum, so it is obvious that the maximum height is given by 
. Thus, we can find this as follows:
So the maximum height the rocket will reach is 66.68ft
<h2>
d. How long is the rocket in the air?</h2>
The rocket is in the air until it hits the ground. This can be found setting 
, so:
We can't have negative value of time, so the only correct option is 
and rounding to the nearest hundredth we have definitively:
Answer:
950 + 175
Step-by-step explanation:
to find the original price before the sale, you need to add.
Answer:
Area of a trapezium = 1/2(a+b)×h
where a and b are parallel sides of the trapezium
h is the height
First question
We must first find the height of the trapezium using Pythagoras theorem
That's
h² = 8² -3²
h =√ 64 - 9
h = √ 55m
a = 7m
b = 10+3 = 13m
Area of the trapezoid = 1/2(7+13)×√55
= 1/2×20×√55
= 74.16
= 74m² to the nearest tenth
Second question
We use sine to find the height
sin30° = h/12
h = 12 sin 30°
h = 6 in
Let the other half of the parallel side be x
To find the other half of the parallel side we use Pythagoras theorem
That's
x² = 12²- 6²
x = √144-36
x = √108
x = 6√3 in
So for this trapezoid
a = 9 in
b = (9 + 6√3) in
h = 6 in
Area of the trapezoid = 1/2(9 + 9+6√3) × 6
= 1/2(18+6√3)×6
= 85.176 in²
= 85 in² to the nearest tenth
Hope this helps you
