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2 years ago

9

Can someone please help me witch is the answer 20 points to the one who can answer first

1 answer:

ladessa [460]2 years ago

8 0

First, let's find the slope.

Slope = (7 - (-3)) / (2 - 0) = (7 + 3) / 2 = 10 / 2 = 5

So far our equation looks like: y = 5x + b

Leta plug one of the points into our equation to find b.

-3 = 5(0) + b

Simplify.

-3 = b

The equation is: y = 5x - 3

Answer choice B is correct.

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Need answers as soon as possible, will give brainiest and rate 5/5.

aliya0001 [1]

1. x/-3=-15
x=45

2. -7+3(-12)÷-3
-7+12
5

3. f(-4)=(-4)²-(-4)
f(-4)=16-(-4)
f(-4)=20

4. x-9=17

5. 2x+3=35

6. -8-12-(-20)
-20-(-20)
0

7. -2(-3)²(-1)
-2(9)(-1)
-18(-1)
18

8. x-(-2)

9. subtract 7 then divide by -2

10. 6+(-18)+(-13)+9
-12-4
-16

11. 5x=11

12. division property

13. -3³ = -27

14. x/2-3=7
x/2=10
x=20

15. 2x-5=15

16. x/-4-(-8)=12
x/-4=4
x=-16

17. 168

18. 16-20-(-8)-9
-4-(-8)-9
4-9
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3 0

3 years ago

Read 2 more answers

I needs help please and tank chu

PIT_PIT [208]

9514 1404 393

Answer:

C {2, 4, 9, 16}

Step-by-step explanation:

The domain is the list of numbers at the tails of the arrows.

The range is the list of numbers at the heads of the arrows: {2, 4, 9, 16}.

5 0

2 years ago

Find 1 + 3 + 5 + … + 389.

user100 [1]

Answer:

The rule is +2

This is the 194th term

Step-by-step explanation:

This is an arithmetic sequence because 2 is added every time.

2x + 1 = 389

2x = 388

x = 194

194* 2 + 1 = 389

mark brainliest please!

3 0

1 year ago

Read 2 more answers

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

babunello [35]

The 4th one goes with the 1st box
The 2nd one goes with the 2nd box
The last one goes with the 3rd box

3 0

2 years ago

The surface area of a right circular cone of radius r and height h is S = πr√ r 2 + h 2 , and its volume is V = 1 3 πr2h. What i

kirill115 [55]

Answer:

Required largest volume is 0.407114 unit.

Step-by-step explanation:

Given surface area of a right circular cone of radious r and height h is,

$S=\pi r\sqrt{r^2+h^2}$

and volume,

$V=\frac{1}{3}\pi r^2 h$

To find the largest volume if the surface area is S=8 (say), then applying Lagranges multipliers,

$f(r,h)=\frac{1}{3}\pi r^2 h$

subject to,

$g(r,h)=\pi r\sqrt{r^2+h^2}=8\hfill (1)$

We know for maximum volume $r\neq 0$ . So let $\lambda$ be the Lagranges multipliers be such that,

$f_r=\lambda g_r$

$\implies \frac{2}{3}\pi r h=\lambda (\pi \sqrt{r^2+h^2}+\frac{\pi r^2}{\sqrt{r^2+h^2}})$

$\implies \frac{2}{3}r h= \lambda (\sqrt{r^2+h^2}+\frac{ r^2}{\sqrt{r^2+h^2}})\hfill (2)$

And,

$f_h=\lambda g_h$

$\implies \frac{1}{3}\pi r^2=\lambda \frac{\pi rh}{\sqrt{r^2+h^2}}$

$\implies \lambda=\frac{r\sqrt{r^2+h^2}}{3h}\hfill (3)$

Substitute (3) in (2) we get,

$\frac{2}{3}rh=\frac{r\sqrt{R^2+h^2}}{3h}(\sqrt{R^2+h^2+}+\frac{r^2}{\sqrt{r^2+h^2}})$

$\implies \frac{2}{3}rh=\frac{r}{3h}(2r^2+h^2)$

$\implies h^2=2r^2$

Substitute this value in (1) we get,

$\pi r\sqrt{h^2+r^2}=8$

$\implies \pi r \sqrt{2r^2+r^2}=8$

$\implies r=\sqrt{\frac{8}{\pi\sqrt{3}}}\equiv 1.21252$

Then,

$h=\sqrt{2}(1.21252)\equiv 1.71476$

Hence largest volume,

$V=\frac{1}{3}\times \pi \times\frac{\pi}{8\sqrt{3}}\times 1.71476=0.407114$

3 0

2 years ago