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vampirchik [111]
2 years ago
15

Simplify the expressions below. 8-13-(-4)= -1 b. 4-(-7)+(-2)= 9 c. -7+3-20= -24

Mathematics
1 answer:
marysya [2.9K]2 years ago
4 0
(a) \-1,\ (b) \9
(c) \-24 if 8m not wrong thats the answer
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What number am i missing please only tell me the one missing!!!
makvit [3.9K]

Answer:

16

Step-by-step explanation:

40 can be multiplied by 5, 8 times. 8 multiplied by 2 is 16.

4 0
2 years ago
A professor wants to award prizes for 1st, 2nd, 3rd, 4th and 5th in the class of 30. In how many ways can the prizes be awarded
aniked [119]

Answer:

Selection =  17100720\ ways

Step-by-step explanation:

Given

Students = 30

Positions = 5 i.e. first to fifth

Required

Determine number of selection

1st position = Any of the 30 students

2nd position = Any of the 29 students

3rd position = Any of the 28 students

4th position = Any of the 27 students

5th position = Any of the 26 students

Number of selection is then calculated as:

Selection =  30 * 29 * 28 * 27 * 26

Selection =  17100720\ ways

8 0
3 years ago
9​in the power of 3 is equal to 3in the power of M, What number is M?<br> Help​ me please~°~​
zhannawk [14.2K]

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6

Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
What is the GCF of 35,42,38
lbvjy [14]
The greatest common factor (GCF) of 35, 38, and 42 is 1.

There are no common prime numbers, so the GCF is 1.
8 0
2 years ago
SinA=√1-x÷√1+X<br> Find the value of cosA
Irina-Kira [14]

The value of cos A is √(1 + x²)/ (1 - x²) /√1 + x

<h3>Trigonometric ratios</h3>

It is important to note that

sin A = opposite/ hypotenuse

cos A = adjacent/ hypotenuse

Then,

opposite = \sqrt{1} - x

Hypotenuse = \sqrt{1} + x

Let's find the adjacent side using the Pythagorean theroem

(\sqrt{1} + x)^2 = (\sqrt{1 -x } )^2 + x^2

1 + x^2 = 1 - x^2 + x^2

x = \sqrt{\frac{1 + x^2}{1 -x^2} }

cos A = x/hypotenuse

cos A = \frac{\sqrt{\frac{1+x^2}{1 -x^2} } }{\sqrt{1} +x}

cos A = √(1 + x²)/ (1 - x²) /√1 + x

Thus, the value of cos A is √(1 + x²)/ (1 - x²) /√1 + x

Learn more about trigonometric identities here:

brainly.com/question/7331447

#SPJ1

6 0
1 year ago
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