Answer:
The correct option is 1.
Step-by-step explanation:
The given function is
![f(x)=\int_0^x\sin (t^2)dt](https://tex.z-dn.net/?f=f%28x%29%3D%5Cint_0%5Ex%5Csin%20%28t%5E2%29dt)
We need to find the value of f '(1).
![f'(x)=\frac{d}{dx}f(x)](https://tex.z-dn.net/?f=f%27%28x%29%3D%5Cfrac%7Bd%7D%7Bdx%7Df%28x%29)
![f'(x)=\frac{d}{dx}(\int_0^x\sin (t^2)dt)](https://tex.z-dn.net/?f=f%27%28x%29%3D%5Cfrac%7Bd%7D%7Bdx%7D%28%5Cint_0%5Ex%5Csin%20%28t%5E2%29dt%29)
![[\because \frac{d}{dx} (\int_0^xf(t)dt)=f(x)]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Cfrac%7Bd%7D%7Bdx%7D%20%28%5Cint_0%5Exf%28t%29dt%29%3Df%28x%29%5D)
Substitute x=1 in the above function to find the value of f'(1).
![f'(1)=\sin (1^2)](https://tex.z-dn.net/?f=f%27%281%29%3D%5Csin%20%281%5E2%29)
![f'(1)=0.841470984808](https://tex.z-dn.net/?f=f%27%281%29%3D0.841470984808)
![f'(1)=0.841](https://tex.z-dn.net/?f=f%27%281%29%3D0.841)
The value of f'(1) is 0.841. Therefore the correct option is 1.
Let's break it down quick
since (8*5) is in parenthesis, you have to do it first which would equal 40. 10*2=20*8 is 160. Since there is a negative in between that and 3*40 you must solve 3*40 first, which equals 120. Now,
160-120= 40
The answer to the question is 40.
Answer:
4
Step-by-step explanation:
Because there are 10 pices and 4 of them are greater than 6
Answer:
3. Yes, because it can be written as 23/100
Step-by-step explanation:
Answer:
-69
Step-by-step explanation:
16-(5)(16)-(5)
16x5=80
16-80-5
16-80=-64
-64-5=-69