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4 years ago

6

I'd really appreciate it if anyone helped! :)

1 answer:

Sophie [7]4 years ago

4 0

Vertical translation of 3 units down

the graph of g(x) = - 3 + | x| is the graph of f(x) = | x| moved 3 units down ( - 3 ) vertically

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Please help!!!!!!!!!!!!!! I need help please!!!!!!

julsineya [31]

Answer:

c

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

What is the answer for -390=26c+52<br><br> Choices:<br> 1: C=17<br> 2: C=-13<br> 3: C=13<br> 4: C=17

just olya [345]

Answer:

C=-17

Step-by-step explanation:

-390-52=-442

-442/26=-17

-17

8 0

3 years ago

One marble is picked at random and NOT replaced from a box that has 3 red marbles, 4 green marbles 2 blue marbles and one yellow

yKpoI14uk [10]

Answer:

3/9

Step-by-step explanation:

because there are total 9 marbles. 3 red, 4 green and 2 blue.so the probability is 3/9.

6 0

3 years ago

When a snowstorm hit the town of Clarkesville, there already were 4 inches of snow on the ground. The storm lasted for 2 hours,

Olin [163]

Answer:

Rate of snow fall per hour ≥ 1 inches per hour

Step-by-step explanation:

Given:

Amount of snow already settled = 4 inches

Time period of snow fall = 2 hour

New amount of snow = least 6 inches

Computation:

Extra amount of snow ≥ New amount of snow - Amount of snow already settled

Extra amount of snow ≥ 6 - 4

Extra amount of snow ≥ 2 inches

Rate of snow fall per hour ≥ Extra amount of snow / Time period of snow fall

Rate of snow fall per hour ≥ 2 / 2

Rate of snow fall per hour ≥ 1 inches per hour

8 0

4 years ago

11. Through (-3,-5), perpendicular to -2x - 5y = -19

Grace [21]

Answer:

11) D. y=5/2x+5/2 , 12) B. y=8/5x+69/5, 14) A. y=-9/5x-67/5

Step-by-step explanation:

11) The function of the perpendicular line can be found in terms of its slope and a given point by this formula:

$y-y_{o} = m_{\perp}\cdot (x-x_{o})$

Where:

$x_{o}$ , $y_{o}$ - Components of the given point, dimensionless.

$m_{\perp}$ - Slope, dimensionless.

Besides, a slope that is perpendicular to original line can be calculated by this expression:

$m_{\perp} = -\frac{1}{m}$

Where $m$ is the slope of the original line, dimensionless.

The original slope is determined from the explicitive form of the given line:

$-2\cdot x - 5\cdot y = -19$

$2\cdot x +5\cdot y = 19$

$5\cdot y = 19 - 2\cdot x$

$y = \frac{19}{5} -\frac{2}{5}\cdot x$

The original slope is $-\frac{2}{5}$ , and the slope of the perpendicular line is:

$m_{\perp} = -\frac{1}{\left(-\frac{2}{5}\right) }$

$m_{\perp} = \frac{5}{2}$

If $x_{o} = -3$ , $y_{o} = -5$ and $m_{\perp} = \frac{5}{2}$ , then:

$y-(-5) = \frac{5}{2}\cdot [x-(-3)]$

$y + 5 = \frac{5}{2}\cdot x +\frac{15}{2}$

$y = \frac{5}{2}\cdot x +\frac{5}{2}$

The right answer is D.

12) The function of the parallel line can be found in terms of its slope and a given point by this formula:

$y-y_{o} = m_{\parallel}\cdot (x-x_{o})$

Where:

$x_{o}$ , $y_{o}$ - Components of the given point, dimensionless.

$m_{\parallel}$ - Slope, dimensionless.

Its slope is the slope of the given, which must be transformed into its explicitive form:

$-8\cdot x + 5\cdot y = 89$

$5\cdot y = 89 +8\cdot x$

$y = \frac{89}{5}+\frac{8}{5} \cdot x$

The slope of the parallel line is $\frac{8}{5}$ .

If $x_{o} = -8$ , $y_{o} = 1$ and $m_{\parallel} = \frac{8}{5}$ , then:

$y-1 = \frac{8}{5}\cdot [x-(-8)]$

$y-1 = \frac{8}{5}\cdot x +\frac{64}{5}$

$y = \frac{8}{5}\cdot x +\frac{69}{5}$

The correct answer is B.

14) The function of the perpendicular line can be found in terms of its slope and a given point by this formula:

$y-y_{o} = m_{\perp}\cdot (x-x_{o})$

Where:

$x_{o}$ , $y_{o}$ - Components of the given point, dimensionless.

$m_{\perp}$ - Slope, dimensionless.

Besides, a slope that is perpendicular to original line can be calculated by this expression:

$m_{\perp} = -\frac{1}{m}$

Where $m$ is the slope of the original line, dimensionless.

The original slope is determined from the explicitive form of the given line:

$-5\cdot x +9\cdot y = 49$

$9\cdot y = 49+5\cdot x$

$y = \frac{49}{9} +\frac{5}{9}\cdot x$

The original slope is $\frac{5}{9}$ , and the slope of the perpendicular line is:

$m_{\perp} = -\frac{1}{m}$

$m_{\perp} = -\frac{1}{\frac{5}{9} }$

$m_{\perp} = -\frac{9}{5}$

If $x_{o} = -8$ , $y_{o} = 1$ and $m_{\perp} = -\frac{9}{5}$ , then:

$y-1 = -\frac{9}{5}\cdot [x-(-8)]$

$y-1 = -\frac{9}{5}\cdot x-\frac{72}{5}$

$y = -\frac{9}{5}\cdot x -\frac{67}{5}$

The correct answer is A.

7 0

3 years ago