Given:
Consider the given gallons are
gallons.
To find:
The number of quarts in
gallons.
Solution:
We know that,
1 gallons = 4 quarts
Using this conversion, we get
![8\dfrac{1}{4}\text{ gallons}=4\times 8\dfrac{1}{4}\text{ quarts}](https://tex.z-dn.net/?f=8%5Cdfrac%7B1%7D%7B4%7D%5Ctext%7B%20gallons%7D%3D4%5Ctimes%208%5Cdfrac%7B1%7D%7B4%7D%5Ctext%7B%20quarts%7D)
![8\dfrac{1}{4}\text{ gallons}=4\times \dfrac{32+1}{4}\text{ quarts}](https://tex.z-dn.net/?f=8%5Cdfrac%7B1%7D%7B4%7D%5Ctext%7B%20gallons%7D%3D4%5Ctimes%20%5Cdfrac%7B32%2B1%7D%7B4%7D%5Ctext%7B%20quarts%7D)
![8\dfrac{1}{4}\text{ gallons}=4\times \dfrac{33}{4}\text{ quarts}](https://tex.z-dn.net/?f=8%5Cdfrac%7B1%7D%7B4%7D%5Ctext%7B%20gallons%7D%3D4%5Ctimes%20%5Cdfrac%7B33%7D%7B4%7D%5Ctext%7B%20quarts%7D)
![8\dfrac{1}{4}\text{ gallons}=33\text{ quarts}](https://tex.z-dn.net/?f=8%5Cdfrac%7B1%7D%7B4%7D%5Ctext%7B%20gallons%7D%3D33%5Ctext%7B%20quarts%7D)
Therefore, there are 33 quarts in
gallons.
Answer:
The number of bacteria after
will be ![3840](https://tex.z-dn.net/?f=3840)
Step-by-step explanation:
Given the initially 30 bacteria present in the culture.
Also, the number of bacteria got doubled every hour.
So, using the equation
![A=A_0r^{n-1}](https://tex.z-dn.net/?f=A%3DA_0r%5E%7Bn-1%7D)
Where
is number of bacteria after
hours.
is bacteria present initially.
is the common ration, in our problem it is given that bacteria doubles every hour. So, ![r=2](https://tex.z-dn.net/?f=r%3D2)
And
is the number of hours. In our problem we need amount of bacteria at the end of
hours. So, ![n=8](https://tex.z-dn.net/?f=n%3D8)
Plugging values in the formula we get,
![A=30(2)^{8-1}\\A=30\times 2^7\\A=30\times 128\\A=3840](https://tex.z-dn.net/?f=A%3D30%282%29%5E%7B8-1%7D%5C%5CA%3D30%5Ctimes%202%5E7%5C%5CA%3D30%5Ctimes%20128%5C%5CA%3D3840)
So, number of bacteria after
will be ![3840](https://tex.z-dn.net/?f=3840)
Answer:
here is your answer....
Step-by-step explanation:
lets take x as 8
t(8)=3*8
t(8)=24
Therefore:
we get t(x)=24 from equation t(x)=3x
9514 1404 393
Answer:
20.3
Step-by-step explanation:
The distance formula can be used to find the side lengths.
d = √((x2 -x1)^2 +(y2 -y1)^2)
For the first two points, ...
d = √((3 -(-2))^2 +(6 -3)^2) = √(5^2 +3^2) = √34 ≈ 5.83
For the next two points, ...
d = √((2 -3)^2 +(-2-6)^2) = √(1 +64) = √65 ≈ 8.06
For the last and first points, ...
d = √((-2-2)^2 +(3-(-2)^2) = √(16 +25) = √41 ≈ 6.40
Then the sum of the side lengths is ...
5.83 +8.06 +6.40 = 20.29 ≈ 20.3
The perimeter of the triangle is about 20.3 units.
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