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Andrews [41]
3 years ago
13

If you vertically stretch the exponential function f(x) = 2* by a factor of 5, what

Mathematics
1 answer:
zloy xaker [14]3 years ago
5 0

Answer:

f(x)=5(2^x)

Step-by-step explanation:

We have been given the parent function

We have the transformation rule:

Rule: If the parent function y =f(x) is stretched vertically by a factor 'k' then the equation becomes y=kf(x).

Here, the exponential function  vertically stretched by a factor 5, hence, k = 5.

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4 0
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Read 2 more answers
Find the distance between the given points.
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The distance would be 4 units and you would go 4 to the right

I hope this helps :)

Step-by-step explanation:

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3 years ago
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Suppose you earn 3% on a $1,200 deposit for 5 years. Explain how the simple interest is affected if the rate is increased by 1%.
coldgirl [10]
\bf ~~~~~~ \textit{Simple Interest Earned}\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$1200\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
t=years\to &5
\end{cases}
\\\\\\
I=1200(0.03)(5)\implies \boxed{I=180}\\\\
-------------------------------

\bf ~~~~~~ \textit{Simple Interest Earned increased by 1\%}\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$1200\\
r=rate\to 4\%\to \frac{4}{100}\to &0.04\\
t=years\to &5
\end{cases}
\\\\\\
I=1200(0.04)(5)\implies \boxed{I =240}\\\\
-------------------------------

\bf ~~~~~~ \textit{Simple Interest Earned increased by 1 year}\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$1200\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
t=years\to &6
\end{cases}
\\\\\\
I=1200(0.03)(6)\implies \boxed{I =216}
8 0
4 years ago
Answers? with explanations
Alinara [238K]
Okay, so basically we have:
w as width; and 6+w as length

Perimeter=2w+2l

just substitute it with the values of width and length

P=2w+2(6+w)
P=2w+12+2w
P=4w+12

So, the answer is letter B.
4 0
4 years ago
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