Answer:
Suppose a population of rodents satisfies the differential equation dP 2 kP dt = . Initially there are P (0 2 ) = rodents, and their number is increasing at the rate of 1 dP dt = rodent per month when there are P = 10 rodents.
How long will it take for this population to grow to a hundred rodents? To a thousand rodents?
Step-by-step explanation:
Use the initial condition when dp/dt = 1, p = 10 to get k;
Seperate the differential equation and solve for the constant C.
You have 100 rodents when:
You have 1000 rodents when:
Answer:
y=4
Step-by-step explanation:
Answer:
your answer is 3 this is a simple equation type this into to brainly next time it will give you the answer
Answer:
5 students from Westville Elementary school re on a field trip. They come to a hot dog stand and no one has money. One student's parents has a tab at the hot dog stand. So the student, along with the four others, decide to order food and put it on the tab. Each hot dog is 1/3 of a dollar. They would like to know how much they are in debt.
5 times the negative (-1/3) for each hot dog.
-1 and 2/3 dollars
Glad I was able to help!!
Answer:
f(6) = 1
Step-by-step explanation:
Function:
f(x) = -2/3x + 5
f(6) = -2/3(6) + 5
f(6) = -4 + 5
f(6) = 1
