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qwelly [4]
3 years ago
5

It is important to re-evaluate financial goals periodically. In which of the following situations would it be necessary to chang

e an existing financial goal?
a. You fell sharply behind your expected schedule with regard to saving.

b. You recovered from an unexpected expense and are rattled that you did not see it coming.

c. You married, and your spouse has a similar financial goal.

d. You came across unexpected income.



Please select the best answer from the choices provided
A
B
C
D
Mathematics
2 answers:
sergiy2304 [10]3 years ago
4 0
The answer to the question is A
vova2212 [387]3 years ago
3 0
The answer is A. <span>You fell sharply behind your expected schedule with regard to saving. 
You're financial goal and planning should be designed to fulfill a realistic expectation on your financial situation somewhere in the future.
When you're behind the schedule, you should either bring down the threshold for your financial goals to make it more realistic to achieve or find  another source of income so your target could still be fulfilled even though you have to make additional sacrifice</span>
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Pls help me ! L need help here
Sophie [7]

Answer:

H. 40 inches

Step-by-step explanation:

On Wednesday, he is 40 inches taller. ... That would make 5 days of growth, for 100 inches. But this is only 3 days therefore he would grow 40 inches taller

5 0
2 years ago
There are 1,295 students attending a small university.There are 714 women enrolled.What percent of the students are women?
BARSIC [14]
Total students = 1295

Number of women = 714

Percentage of women = 714/1295 x 100 = 55.14%

------------------------------------------------------------------
Answer: 55.14% of the students are women.
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3 0
3 years ago
What are the solutions of the compound inequality 2d + 3 ≤ –11 or 3d – 9 &gt; 15?
jolli1 [7]

Answer:

A. d ≤ –7 or d > 8.

Step-by-step explanation:

Given  : 2d + 3 ≤ –11 or 3d – 9 > 15.

To find : What are the solutions of the compound inequality .

Solution : We have given 2d + 3 ≤ –11 or 3d – 9 > 15.

For  2d + 3 ≤ –11

On subtracting both sides by 3

2d  ≤ –11 - 3 .

2d  ≤ –14.

On dividing both sides by 2 .

d  ≤ –7.

For  3d – 9 > 15.

On adding both sides by 9.

3d > 15 + 9 .

3d > 24 .

On dividing both sides by 3 .

d > 8 .

So, A. d ≤ –7 or d > 8.

Therefore,  A. d ≤ –7 or d > 8.

7 0
3 years ago
How do you do this question?
katen-ka-za [31]

Answer:

0

Step-by-step explanation:

∫ sin²(x) cos(x) dx

If u = sin(x), then du = cos(x) dx.

∫ u² du

⅓ u³ + C

⅓ sin³(x) + C

Evaluate between x=0 and x=π.

⅓ sin³(π) − ⅓ sin³(0)

0

7 0
3 years ago
Read 2 more answers
find the slope/ rate of change of the two points. Identify whether it is positive, negative, undefined or zero. (0,15) and (16,-
weqwewe [10]

Answer:1.7 its positive

Step-by-step explanation: 0,15 .  16,-12

y1-y2/x1-x2

15-(-12)= 27

0-16= 16

27/16 = 1.7

4 0
3 years ago
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