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3 years ago

The Circle with a center (10,1) and the radius 5 has equation

Mathematics

1 answer:

liberstina [14]3 years ago

5 0

<h3>Answer: (x-10)^2 + (y-1)^2 = 25</h3>

============================================

Explanation:

The general template of a circle is

(x-h)^2 + (y-k)^2 = r^2

Where,

(h,k) is the center
r is the radius

We are given (10,1) as the center so (h,k) = (10,1) meaning that h = 10 and k = 1 pair up together.

r = 5 is the given radius.

-----

Plug the values h = 10, k = 1, r = 5 into the equation to get:

(x-h)^2 + (y-k)^2 = r^2

(x-10)^2 + (y-1)^2 = 5^2

(x-10)^2 + (y-1)^2 = 25

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bekas [8.4K]

Step-by-step explanation:

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1 year ago

Consider the function f(x) =2x-6 find f(2)

tester [92]

Step-by-step explanation:

✧ $\underline{ \underline{ \large{ \tt{G \: I \: V \: E\: N}}} } :$

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✧ $\underline{ \underline{ \large{ \tt{T\: O \: \: F\: I\: N\: D}}}}:$

value of f ( 2 )

✧ $\underline{ \underline{ \large{ \tt{S \:O \: L \: U \: T \: I \: O \: N}}}} :$

❀ $\large{ \text{When \: x = 2 ,\: f}(2) = 2 \tt{ \times 2 - 6}}$

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Hope I helped ! ♡

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neonofarm [45]

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3 years ago