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aleksklad [387]
2 years ago
15

PLEASE HELP ME !!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
dsp732 years ago
7 0

Answer:

the required answer is 64

Step-by-step explanation:

b/4 =16

b = 16 × 4

= 64

nevsk [136]2 years ago
4 0

Answer:

B /4 =16

Step-by-step explanation:

multiply by 4 and the answer is 64

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Festus bought a computer at $736.34, Apple iPad at $249.99, and a printer at 381.23. The sales tax rate is %6. What is the total
tatuchka [14]

The total purchase price including sales tax will be $1449.6136

<em><u>Explanation</u></em>

Festus bought a computer at $736.34, Apple iPad at $249.99 and a printer at $381.23

So, the <u>total price of all three items</u> =(736.34+249.99+381.23) dollar = 1367.56 dollar.

The sales tax rate is 6%. So, <u>the amount of sales tax</u> =(1367.56*0.06) dollar= 82.0536 dollar.

Thus, the total purchase price including sales tax will be:  (1367.56 + 82.0536) dollar = 1449.6136 dollar

6 0
3 years ago
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3 0
3 years ago
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The diameter of a particle of contamination (in micrometers) is modeled with the probability density function f(x)= 2/x^3 for x
natulia [17]

Answer:

a) 0.96

b) 0.016

c) 0.018

d) 0.982

e) x = 2

Step-by-step explanation:

We are given with the Probability density function f(x)= 2/x^3 where x > 1.

<em>Firstly we will calculate the general probability that of P(a < X < b) </em>

       P(a < X < b) =  \int_{a}^{b} \frac{2}{x^{3}} dx = 2\int_{a}^{b} x^{-3} dx

                            = 2[ \frac{x^{-3+1} }{-3+1}]^{b}_a   dx    { Because \int_{a}^{b} x^{n} dx = [ \frac{x^{n+1} }{n+1}]^{b}_a }

                            = 2[ \frac{x^{-2} }{-2}]^{b}_a = \frac{2}{-2} [ x^{-2} ]^{b}_a

                            = -1 [ b^{-2} - a^{-2}  ] = \frac{1}{a^{2} } - \frac{1}{b^{2} }

a) Now P(X < 5) = P(1 < X < 5)  {because x > 1 }

     Comparing with general probability we get,

     P(1 < X < 5) = \frac{1}{1^{2} } - \frac{1}{5^{2} } = 1 - \frac{1}{25} = 0.96 .

b) P(X > 8) = P(8 < X < ∞) = 1/8^{2} - 1/∞ = 1/64 - 0 = 0.016

c) P(6 < X < 10) = \frac{1}{6^{2} } - \frac{1}{10^{2} } = \frac{1}{36} - \frac{1}{100 } = 0.018 .

d) P(x < 6 or X > 10) = P(1 < X < 6) + P(10 < X < ∞)

                                = (\frac{1}{1^{2} } - \frac{1}{6^{2} }) + (1/10^{2} - 1/∞) = 1 - 1/36 + 1/100 + 0 = 0.982

e) We have to find x such that P(X < x) = 0.75 ;

               ⇒  P(1 < X < x) = 0.75

               ⇒  \frac{1}{1^{2} } - \frac{1}{x^{2} } = 0.75

               ⇒  \frac{1} {x^{2} } = 1 - 0.75 = 0.25

               ⇒  x^{2} = \frac{1}{0.25}   ⇒ x^{2} = 4 ⇒ x = 2  

Therefore, value of x such that P(X < x) = 0.75 is 2.

8 0
2 years ago
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Answer:

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2 years ago
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hoa [83]

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