Find two consecutive odd intergers whose sum is 116

1 answer:

3 0

x+(x+2)=116. Simplify that to 2x+2=116, subtract 2 from both sides to get 2x=114, and then divide both sides by 2 to get x=57. That would be the first integer, so the second would then be 59. So there's your answer: The two consecutive odd integers are 57 and 59.Answer:

Step-by-step explanation:

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A total of 815 tickets were sold for the school play. They were either adult tickets or student tickets. There were 65 more stud

kvv77 [185]

Answer:

375 Adult Tickets.

Step-by-step explanation:

Here, we can simply set up an equation using variable x in place of the unknown student/adult tickets.

x = # of adult tickets sold

x + 65 = # of student tickets sold.

1) x + x + 65 = 815 (set both ticket amounts equal to the total)

2) 2x + 65 = 815 (added common variables together)

3) 2x = 750 (negated the +65, subtracted it from both sides)

4) x = 375 (divided both sides by 2)

5) 815 - 375 = 440 (subtracted the x from the total number of adult tickets, to recieve the amount of childrens' tickets.

Therefore,

Since there were fewer adult tickets sold (-65), 375 is the number of adult tickets, and 440 is the number of student tickets.

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2 years ago

An environmental science teacher at a high school with a large population of students wanted to estimate the proportion of stude

AnnZ [28]

Answer:

60 students

Step-by-step explanation:

The confidence interval of a proportion is given by:

$p\pm z*\sqrt{\frac{p*(1-p)}{n} }$

Where 'p' is the proportion of students who responded 'yes', 'z' is the z-score for a 95% confidence interval (which is known to be 1.960), and 'n' is the number of students in the sample.

If the confidence interval is from 0.584 to 0.816, then:

$p=\frac{0.584+0.816}{2}=0.7 \\0.816-0.584=2*(1.96*\sqrt{\frac{p*(1-p)}{n}}) \\0.116=1.96*\sqrt{\frac{0.7*(1-0.7)}{n}}\\n=16.8966^2*(0.7*0.3)\\n=60\ students$