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serg [7]
3 years ago
10

Lucia knows the fourth term in a sequence is 55 and the ninth term in the same sequence is 90. Explain how she can find the comm

on difference for the sequence. then use the common difference to find the second term of the sequence.
Mathematics
1 answer:
Andreyy893 years ago
4 0
Using the formula for the nth term of an arithmetic progression.
an = a + (n - 1)d
a(4) = a + 3d = 55
a(9) = a + 8d = 90
a(9) - a(4) => 5d = 35
d = 35/5 = 7.
From a(4): a = 55 - 3d = 55 - 3(7) = 55 - 21 = 34

a(2) = a + d = 34 + 7 = 41.

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Answer:

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Step-by-step explanation:

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Give a geometric interpretation of the triangle inequality
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Two chemists working for a chicken fast-food company, have been producing a very popular sauce. Let’s call then Jesse and Mr. Wh
a_sh-v [17]

Answer:

Check the explanation

Step-by-step explanation:

Let \overline{x} and \overline{y} be sample means of white and Jesse denotes are two random variables.

Given that both samples are having normally distributed.

Assume \overline{x} having with mean \mu_{1} and \overline{y} having mean \mu_{2}

Also we have given the variance is constant

A)

We can test hypothesis as

H0: \mu_{1} =  \mu_{2}H1: \mu_{1} > \mu_{2}

For this problem

Test statistic is

T=\frac{\overline {x}-\overline {y}}{s\sqrt{\frac {1}{n1} +\frac{1}{n2}}}

Where

s=\sqrt{\frac{(n1-1)*s1^{2}+(n2-1)*s2^{2}}{n1+n2-2}}

We have given all information for samples

By calculations we get

s=2.41

T=2.52

Here test statistic is having t-distribution with df=(10+7-2)=15

So p-value is P(t15>2.52)=0.012

Here significance level is 0.05

Since p-value is <0.05 we are rejecting null hypothesis at 95% confidence.

We can conclude that White has significant higher mean than Jesse. This claim we can made at 95% confidence.

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3 years ago
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Answer:

C or d

Step-by-step explanation:

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A person must score in the upper 8% of the population on an IQ test to qualify for membership in MENSA, the international high-I
Cloud [144]

Answer:

A person must get an IQ score of at least 138.885 to qualify.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 115, \sigma = 17

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Top 8%, so at least the 100-8 = 92th percentile.

Scores of X and higher, in which X is found when Z has a pvalue of 0.92. So X when Z = 1.405.

Z = \frac{X - \mu}{\sigma}

1.405 = \frac{X - 115}{17}

X - 115 = 17*1.405

X = 138.885

A person must get an IQ score of at least 138.885 to qualify.

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