Answer:
After 4 decades, the population of fishes in the pond becomes 48,000 fishes
Step-by-step explanation:
We are told to find the population of fishes in a pond after 4 decades given that the population of the pond doubles after each decade.
A decade is a period of 10 years
For the first decade, the population becomes 3,000 * 2 = 6,000 fishes
For the second decade, the population becomes 6,000 * 2 = 12,000 fishes
For the third decade, the population becomes 12,000 * 2 = 24,000 fishes
and lastly for the fourth decade, the population becomes 24,000 * 2 = 48,000 fishes
Regrouping 21 ones are regrouped as 2 tens and 1 ones.
10
10
01
---
21
You could just make it simple 1+2+3+4+5+6+7+8+164
Answer:
The slope is -2/9
Step-by-step explanation:
9y + 2x = 54
Solve for y to get the equation in the form
y = mx+b where m is the slope and b is the y intercept
Subtract 2x from each side
9y + 2x -2x = -2x+54
9y = -2x+54
Divide by 9
9y/9 = -2x/9 + 54/9
y = -2/9 x +6
The slope is -2/9
Parallel lines have the same slope
Answer:
a) x = -270
b) y = 304/9 or y = 33.78
c) x = -37.8
Step-by-step explanation:
y varies directly with x so y = kx
a)
y = kx
k = y/x
k = 10/-30 = -1/3
So
y = -1/3 x
If y = 90 then
90 = -1/3 x
x = 90 *(-3) = -270
b)
k = y/x
k = -19/-4.5
k = 38/9
So
y = 38/9 x
If x = - 8 then
y = 38/9 *(-8)
y = 304/9 or y = 33.78
c)
k = y/x
k = -4.3 / 12.9
k = - 1/3
So
y = -1/3 x
If y = 12.6 then
12.6 = -1/3 x
x = 12.6 *(-3)
x = -37.8