A set of golf clubs that costs $600 are on sell for 40% off the regular price. What is the sale price of the clubs?

For each level of precision, find the required sample size to estimate the mean starting salary for a new CPA with 95 percent co

Rzqust [24]

Answer:

(a) Margin of error ( E) = $2,000 , n = 54

(b) Margin of error ( E) = $1,000 , n = 216

(c) Margin of error ( E) = $500 , n= 864

Step-by-step explanation:

Given -

Standard deviation $\sigma$ = $7,500

$\alpha$ = 1 - confidence interval = 1 - .95 = .05

$Z_{\frac{\alpha}{2}}$ = $Z_{\frac{.05}{2}}$ = 1.96

let sample size is n

(a) Margin of error ( E) = $2,000

Margin of error ( E) = $Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}$

E = $Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}$

Squaring both side

$E^{2} = 1.96^{2}\times\frac{7500^{2}}{n}$

$n =\frac{1.96^{2}}{2000^{2}} \times 7500^{2}$

n = 54.0225

n = 54 ( approximately)

(b) Margin of error ( E) = $1,000

E = $Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}$

1000 = $Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}$

Squaring both side

$1000^{2} = 1.96^{2}\times\frac{7500^{2}}{n}$

$n =\frac{1.96^{2}}{1000^{2}} \times 7500^{2}$

n = 216

(c) Margin of error ( E) = $500

E = $Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}$

500 = $Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}$

Squaring both side

$500^{2} = 1.96^{2}\times\frac{7500^{2}}{n}$

$n =\frac{1.96^{2}}{500^{2}} \times 7500^{2}$

n = 864

7 0

3 years ago

Kyle ran 200 yard in 40 sec. How many feet could she ran each sec ?

Ghella [55]

5 feet a second. and now i am just saying things because this website has to make me have 20 words

8 0

3 years ago

Can a fraction that has 176/9 be simplified

maria [59]

No they cannot be simplified together from what I know

6 0

3 years ago

Read 2 more answers

Can someone smart please help me?

ollegr [7]

Hello!

For a:

How I would do this, is I would first say if all 46 animals (heads) were chickens, how many legs would there be? Each chicken has 2 legs, so 46 * 2 = 92. The total amount of legs is 96 as stated in the question, so if all of the animals were chickens, the farmer would be 4 legs short.

Now to add rabbits into the equation. Rabbits have 4 legs, and chickens have 2. You want to find the difference between the two, because as you add rabbits to the animals the farmer has, then you have to take away chickens at the same time. 4-2 = 2, so for each rabbit you replace, you add 2 legs.

Since the farmer is 4 legs short with all chickens, then you just divide that 4 by the 2 legs you add by replacing a chicken with a rabbit.

4 / 2 = 2 rabbits

So that means there are 2 rabbits. Since there are 46 heads in total, if 2 are rabbits, that means there are 44 chickens.

So there are 44 chickens and 2 rabbits.

b)

You can follow the same steps: I'm assuming all are child tickets for now:

3.05 * 100 = $305

And now you find how much money short you are.

498.6 - 305 = 193.6

Next, you find the difference in the ticket costs.

5.25 - 3.05 = 2.20

And you divide to find the number of adult tickets.

193.6 / 2.2 = 88

Since 100 tickets were sold, and 88 adult tickets were sold, that means 12 child tickets were sold.

7 0

3 years ago

Distributive property<br> 7(*+2)+3=73

Elina [12.6K]

X=8 would you like me to explain why?

4 0

3 years ago