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Mademuasel [1]
3 years ago
5

Which expression is equivalent to 10/21

Mathematics
2 answers:
Gala2k [10]3 years ago
4 0

Answer:

20/ 42 is equivalent....

dexar [7]3 years ago
3 0

Answer:

\frac{20}{42}

Step-by-step explanation:

In order to find the answer to this question you just have to multiply the numerator and denominator by any integer.

In this case:

\frac{10}{21}

Multiply by 2:

10 \times 2=20

21\times2=42

\frac{10}{21} =\frac{20}{42}

Hope this helps.

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Kevin rented a truck for one day. there was a base fee of $17.99, and there was an additional charge of 95 cents for each mile d
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Answer:

Step-by-step explanation:

Base fee = $17.99

Additional charge = $0.95 for each mile driven

If Kevin paid $157.64 when he returned the truck and we want to find out how many miles he drove the truck, step 1 would be to subtract the base fee.

157.65 - 17.99 = 139.65

This means that the remaining $139.65 is how much he paid for the miles he drove.

Since we know each mile costs $0.95.

Simply divide $139.65 by $0.95 to work out how many miles he drove.

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3 years ago
A teacher places n seats to form the back row of a classroom layout. Each successive row contains two fewer seats than the prece
Alex_Xolod [135]

Answer:

The number of seat when n is odd S_n=\frac{n^2+2n+1}{4}

The number of seat when n is even S_n=\frac{n^2+2n}{4}

Step-by-step explanation:

Given that, each successive row contains two fewer seats than the preceding row.

Formula:

The sum n terms of an A.P series is

S_n=\frac{n}{2}[2a+(n-1)d]

    =\frac{n}{2}[a+l]

a = first term of the series.

d= common difference.

n= number of term

l= last term

n^{th} term of a A.P series is

T_n=a+(n-1)d

n is odd:

n,n-2,n-4,........,5,3,1

Or we can write 1,3,5,.....,n-4,n-2,n

Here a= 1 and d = second term- first term = 3-1=2

Let t^{th} of the series is n.

T_n=a+(n-1)d

Here T_n=n, n=t, a=1 and d=2

n=1+(t-1)2

⇒(t-1)2=n-1

\Rightarrow t-1=\frac{n-1}{2}

\Rightarrow t = \frac{n-1}{2}+1

\Rightarrow t = \frac{n-1+2}{2}

\Rightarrow t = \frac{n+1}{2}

Last term l= n,, the number of term =\frac{ n+1}2, First term = 1

Total number of seat

S_n=\frac{\frac{n+1}{2}}{2}[1+n}]

    =\frac{{n+1}}{4}[1+n}]

     =\frac{(1+n)^2}{4}

    =\frac{n^2+2n+1}{4}

n is even:

n,n-2,n-4,.......,4,2

Or we can write

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Here a= 2 and d = second term- first term = 4-2=2

Let t^{th} of the series is n.

T_n=a+(n-1)d

Here T_n=n, n=t, a=2 and d=2

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\Rightarrow t-1=\frac{n-2}{2}

\Rightarrow t = \frac{n-2}{2}+1

\Rightarrow t = \frac{n-2+2}{2}

\Rightarrow t = \frac{n}{2}

Last term l= n, the number of term =\frac n2, First term = 2

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    =\frac{{n}}{4}[2+n}]

     =\frac{n(2+n)}{4}

    =\frac{n^2+2n}{4}  

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