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4 years ago

Which euation has a slope of -7 and a y-intercept of 8?

Mathematics

1 answer:

lorasvet [3.4K]4 years ago

4 0

A: 7x+y=8 is the right answer, because if we move 7x to the other side we get: y=-7x+8

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7²+4(2²+3)/2 please help

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Answer:

i think it's 63

Step-by-step explanation:

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3 years ago

today only, a suit is being sold at a 29% off (discount). The sale price is $284. What was the original price?

natta225 [31]

Answer:

201.64

Step-by-step explanation:

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3 years ago

Read 2 more answers

Factor the following polynomial completely 4x^2-100

Murrr4er [49]

Answer:

4 [ ( x - 5) ( x + 5) ]

Step-by-step explanation:

4x²-100

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3 years ago

Complete the equation, by supplying the missing exponent. m•n2•m3= m 11n2

MaRussiya [10]

Given:

Consider the given equation is:

$m^?\cdot n^2\cdot m^3=m^{11}\cdot n^2$

To find:

The missing exponent.

Solution:

Let x be the missing exponent. Then the given equation can be written as

$m^x\cdot n^2\cdot m^3=m^{11}\cdot n^2$

It can be rewritten as:

$(m^x\cdot m^3)\cdot n^2=m^{11}\cdot n^2$

$m^{x+3}\cdot n^2=m^{11}\cdot n^2$ $[\because a^ma^n=a^{m+n}]$

On comparing the coefficient of m, we get

$x+3=11$

$x=11-3$

$x=8$

Therefore, the value of the missing exponent is 8. So, the complete equation is $m^8\cdot n^2\cdot m^3=m^{11}\cdot n^2$ .

4 0

3 years ago

5 Quick algebra 1 questions for 50 points! Only answer if you know all 5, Tysm! :)

PIT_PIT [208]

The equations of the perpendicular lines are: y = 1/2x + 6, y = 15, y = -x - 2, y = 6x + 3 and y = 1/3x - 4

<h3>How to determine the equations?</h3>

When a linear equation is represented as:

Ax + By = C

The slope (m) is:

m = -A/B

When the linear equation is represented as:

y = mx + c

The slope is m

A line perpendicular to a linear equation that has a slope of m would have a slope of -1/m

Using the above highlights, the equations of the lines are:

6. y = -2x + 5; (2, 7)

The slope is:

m = -2

The perpendicular slope is:

n = 1/2

The equation of the perpendicular line is:

y = n(x - x1) + y1

This gives

y = 1/2(x - 2) + 7

Evaluate

y = 1/2x - 1 + 7

This gives

y = 1/2x + 6

7. y = -5; (11, 15)

The slope is:

m = 0

The perpendicular slope is:

n = 1/0 = undefined

The equation of the perpendicular line is:

y = n(x - x1) + y1

This gives

y = 15

8. Graph ; (-12, 10)

The slope is:

m = (y2 - y1)/(x2 - x1)

Using the points on the graph, we have:

m = (2 - 3)/(3 - 4)

m = 1

The perpendicular slope is:

n = -1

The equation of the perpendicular line is:

y = n(x - x1) + y1

This gives

y = -1(x + 12) + 10

y = -x - 12 + 10

Evaluate

y = -x - 2

9. y = -1/6x + 1; (-2, -9)

The slope is:

m = -1/6

The perpendicular slope is:

n = 6

The equation of the perpendicular line is:

y = n(x - x1) + y1

This gives

y = 6(x + 2) - 9

Evaluate

y = 6x + 12 - 9

This gives

y = 6x + 3

10. 6x + 2y = 14; (12, 0)

The slope is:

m = -6/2

m = -3

The perpendicular slope is:

n = 1/3

The equation of the perpendicular line is:

y = n(x - x1) + y1

This gives

y = 1/3(x - 12) + 0

Evaluate

y = 1/3x - 4

Hence, the equations of the perpendicular lines are: y = 1/2x + 6, y = 15, y = -x - 2, y = 6x + 3 and y = 1/3x - 4

Read more about linear equations at:

brainly.com/question/13763238

#SPJ1

5 0

2 years ago