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Monica [59]
3 years ago
9

What is 32.043 in expanded form?

Mathematics
1 answer:
Ugo [173]3 years ago
8 0
32.043=30+2+0.4+0.003
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Brenda has $500 in her bank account Every week, she withdraws $40 for expeses. Without making any deposits, how many weeks can s
timofeeve [1]

Answer:

7 weeks

Step-by-step explanation:

500-200=300. 300 divided by 40 is 7.5 so 7 weeks

3 0
3 years ago
What is the area of the figure?<br><br> 40 ft2<br> 84 ft2<br> 96 ft2<br> can't be determined
mina [271]

Answer:

A=80\ ft^2

Step-by-step explanation:

we know that

The area of the figure is equal to the area of an isosceles triangle (has two equal sides) plus the area of a rectangle

step 1

Find the area of the triangle

The area of the triangle is equal to

A=\frac{1}{2}bh

we have

b=16\ ft

To find out the height of the triangle Apply the Pythagorean Theorem

10^2=(16/2)^2+h^2

solve for h

100=64+h^2

h^2=100-64

h^2=36

h=6\ ft

<em>Find the area of triangle</em>

A=\frac{1}{2}(16)(6)

A=48\ ft^2

step 2

Find the area of rectangle

The area of rectangle is equal to

A=LW

we have

L=16\ ft\\W=2\ ft

substitute

A=(16)(2)=32\ ft^2

step 3

Find the area of the figure

Adds the areas

A=48+32=80\ ft^2

5 0
3 years ago
Write 9^6 as a power with a base of 3.
Elodia [21]
Sorry i dont know the answer
4 0
3 years ago
Read 2 more answers
Can you please explain and answer this question to me, (don't mind the blue dots, they are the answers of what I think, please l
Fofino [41]
I started with c, but you could’ve started with any box.

So I took the numbers in the c box (the black box in my picture) and divided to see which were multiples of two. They all were.

Then I went to a. All of a’s numbers were divisible by 7.

Then b. Two of them are divisible by 2, so that’s not the answer. None of them were divisible by 7, so there’s your answer!

Then d. Two are divisible by 7, so your rules is divisible by 2.

I hope this helps!

6 0
3 years ago
Help with this question
wlad13 [49]
<h3>A.</h3>

See below for a graph

<h3>B.</h3>

The inverse of a function appears on a graph as the reflection of the function across the line y=x. This is because the inverse relation is effectively the same relation with the variables x and y swapped. Here, the graphs of f(x) and g(x) are mirror images of each other across the line y=x, so we can see they are inverse functions.

The same technology allows us to graph y=f(g(x)) and y=g(f(x)). Both are graphs of y=x, as expected.

7 0
3 years ago
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