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Monica [59]
3 years ago
9

What is 32.043 in expanded form?

Mathematics
1 answer:
Ugo [173]3 years ago
8 0
32.043=30+2+0.4+0.003
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The drama club is selling tickets to a play for each ticket they sell the school receives x dollars and the drama club receives
bogdanovich [222]

The drama club receives $7 for each ticket that they sell.

Step-by-step explanation:

Given,

Amount received by school = x dollars

Amount received by school for 96 tickets = 96x

Amount received by drama club = remaining amount after school

Total amount of 96 tickets = 96x+672

Here,

96x is the share of school

672 is the share of drama club for 96 tickets.

Therefore;

96 tickets = dollars

1 ticket = \frac{672}{96}

1 ticket = 7 dollars

The drama club receives $7 for each ticket that they sell.

Keywords: division, addition

Learn more about division at:

  • brainly.com/question/10364988
  • brainly.com/question/10435816

#LearnwithBrainly

6 0
3 years ago
Twenty two dollars an hours plus 2.25%
amid [387]

Answer:

how long are you working? what are you asking for?

what is the percentage for?

Step-by-step explanation:

8 0
3 years ago
The sum of first three terms of a finite geometric series is -7/10 and their product is -1/125. [Hint: Use a/r, a, and ar to rep
Alchen [17]
Ooh, fun

geometric sequences can be represented as
a_n=a(r)^{n-1}
so the first 3 terms are
a_1=a
a_2=a(r)
a_2=a(r)^2

the sum is -7/10
\frac{-7}{10}=a+ar+ar^2
and their product is -1/125
\frac{-1}{125}=(a)(ar)(ar^2)=a^3r^3=(ar)^3

from the 2nd equation we can take the cube root of both sides to get
\frac{-1}{5}=ar
note that a=ar/r and ar²=(ar)r
so now rewrite 1st equation as
\frac{-7}{10}=\frac{ar}{r}+ar+(ar)r
subsituting -1/5 for ar
\frac{-7}{10}=\frac{\frac{-1}{5}}{r}+\frac{-1}{5}+(\frac{-1}{5})r
which simplifies to
\frac{-7}{10}=\frac{-1}{5r}+\frac{-1}{5}+\frac{-r}{5}
multiply both sides by 10r
-7r=-2-2r-2r²
add (2r²+2r+2) to both sides
2r²-5r+2=0
solve using quadratic formula
for ax^2+bx+c=0
x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}
so
for 2r²-5r+2=0
a=2
b=-5
c=2

r=\frac{-(-5) \pm \sqrt{(-5)^2-4(2)(2)}}{2(2)}
r=\frac{5 \pm \sqrt{25-16}}{4}
r=\frac{5 \pm \sqrt{9}}{4}
r=\frac{5 \pm 3}{4}
so
r=\frac{5+3}{4}=\frac{8}{4}=2 or r=\frac{5-3}{4}=\frac{2}{4}=\frac{1}{2}

use them to solve for the value of a
\frac{-1}{5}=ar
\frac{-1}{5r}=a
try for r=2 and 1/2
a=\frac{-1}{10} or a=\frac{-2}{5}


test each
for a=-1/10 and r=2
a+ar+ar²=\frac{-1}{10}+\frac{-2}{10}+\frac{-4}{10}=\frac{-7}{10}
it works

for a=-2/5 and r=1/2
a+ar+ar²=\frac{-2}{5}+\frac{-1}{5}+\frac{-1}{10}=\frac{-7}{10}
it works


both have the same terms but one is simplified

the 3 numbers are \frac{-2}{5}, \frac{-1}{5}, and \frac{-1}{10}
6 0
3 years ago
The coordinates of the vertices of a rectangle are (-2, 3), (4, -4), (4, 3), and (-2, -4). What are the dimensions of the rectan
erik [133]

Answer:

D

Step-by-step explanation:

Graph the points. Then count the units vertically and horizontally. See picture.

7 0
2 years ago
Which relation is a function?
bixtya [17]
Answer is the first one on left
4 0
2 years ago
Read 2 more answers
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