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Monica [59]
3 years ago
9

What is 32.043 in expanded form?

Mathematics
1 answer:
Ugo [173]3 years ago
8 0
32.043=30+2+0.4+0.003
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Given the equation for the total surface area of a cylinder, solve for the height of the cylinder.
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H= (2pier^2)/ 2pier all subtracted by s so the last equation from the picture.
Hope it helps!
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The thickness of a block is approximately 2 centimeters. How many blocks are in a stack that is 1,000 millimeters high? ( 1 cm =
dangina [55]

Answer:

1block=2cm

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therefore 1block=2×10=20

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Scientists studying biodiversity of amphibians in a rain forest have discovered that the number of species is decreasing by 2% p
kupik [55]

Answer:

Select the correct answer.

Scientists studying biodiversity of amphibians in a rain forest have discovered that the number of species is decreasing by 2% per year. There are currently 74 species of amphibians in the rain forest. Which logarithmic function models the time, , in years, it will take the number of species to decrease to a value of n?

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Step-by-step explanation:

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3 years ago
Write the equation of the parabola that has the vertex at point (3,−12) and passes through the point (0,6).
lana [24]

Answer:

y = 2(x-3)^2 -12

y = -4/9(x-2)^2 +7  bonus

Step-by-step explanation:

The vertex form of a parabola is

y = a(x-h)^2 + k  where (h,k) is the vertex

y = a(x-3)^2 - 12

We have one point given (0,6)

6 = a (0-3) ^2 -12

6 = a (-3)^2 -12

6 = 9a-12

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Divide each side by 9

18/9 = 9a/9

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We follow the same steps for the bonus

y = a(x-2)^2 +7

Substitute the point into the equation

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3 =a (-3)^2 +7

3 = 9a +7

subtract 7 from each side

3-7 = 9a +7-7

-4 = 9a

Divide by 9

-4/9 =a

y = -4/9(x-2)^2 +7

3 0
3 years ago
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I need help on this it’s about trig identities
Cerrena [4.2K]

Answer:

The answer to your question is:

Step-by-step explanation:

1.-

\frac{1 + sin\alpha }{cos\alpha } + \frac{cos\alpha }{1 + sin\alpha } = 2 sec\alpha

\frac{(1 + sin\alpha)^{2} + cos^{2} \alpha  }{cos\alpha (1 + sin\alpha) }

\frac{1  + 2sin\alpha + sin^{2} \alpha+ cos^{2} \alpha  }{cos\alpha + sin\alphacos\alpha  }

\frac{2 + 2sin\alpha }{cos\alpha+ sin\alpha cos\alpha  }

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\frac{2}{cos\alpha }

2sec\alpha

2.-

   sec²x - tanxsecx

\frac{1}{cos^{2}x } - \frac{sinx}{cosx} \frac{1}{cosx}

\frac{1}{cos^{2} x} - \frac{sinx}{cos^{2}x}

\frac{1 - sinx}{cos^{2}x }

\frac{1 - sinx}{1 - sin^{2}x }

\frac{1 - sinx}{(1 - sinx)(1 + sinx)}

\frac{1}{1 + sinx}

3 0
3 years ago
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