Answer:
Step-by-step explanation:
b. p(10.5<x<11.2)= p(x<11.2)-p(x<10.5)
p(x<11.2)= (11.2-9.7)/1 = 1.5 = 0.9332
p(x<10.5)= (10.5-9.7)/1= .8= 0.7881
.9332-0.7881= .1451
c. 9.7-.253, 9.7+.253
9.447, 9.953
Let the existing no. of video games she had be x,
then
(3+x)+2x+5
$70.88
x/67.5=5/100
cross multiply
100x=337.5
divide 100
x=3.375 or 3.38
67.50+3.38= 70.88
So check the picture below
if we check the solutions or zeros for the equation, we get
and as you can see in the picture, the value of "x" when y = 3.5, or the height of the truck is
the truck, ends up with a clearance of
on either side, so, the maximum clearance, the truck can have, those two clearances added together,
Answer:the car was traveling at a speed of 80 ft/s when the brakes were first applied.
Step-by-step explanation:
The car braked with a constant deceleration of 16ft/s^2. This is a negative acceleration. Therefore,
a = - 16ft/s^2
While decelerating, the car produced skid marks measuring 200 feet before coming to a stop.
This means that it travelled a distance,
s = 200 feet
We want to determine how fast the car was traveling (in ft/s) when the brakes were first applied. This is the car's initial velocity, u.
Since the car came to a stop, its final velocity, v = 0
Applying Newton's equation of motion,
v^2 = u^2 + 2as
0 = u^2 - 2 × 16 × 200
u^2 = 6400
u = √6400
u = 80 ft/s
