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lara31 [8.8K]
3 years ago
9

Find the largest value of $x$ such that $3x^2 + 17x + 15 = 5.$

f%20%24x%24%20such%20that%20%243x%5E2%20%2B%2017x%20%2B%2015%20%3D%205.%24" id="TexFormula1" title="Find the largest value of $x$ such that $3x^2 + 17x + 15 = 5.$" alt="Find the largest value of $x$ such that $3x^2 + 17x + 15 = 5.$" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Zinaida [17]3 years ago
4 0

The largest <em>x</em> that satisfies

3x^2+17x+15=5

is the largest solution to

3x^2+17x+10=0

We have

3x^2+17x+10=(3x+2)(x+5)=0

\implies x=-\dfrac23\text{ or }x=-5

and so the largest value of <em>x</em> we want is -2/3.

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Welp. I sure hope you like the Pythagorean theorem...
Top line:
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Step-by-step explanation:

−4x+5−13x+39=180

Step 1: Simplify both sides of the equation.

−4x+5−13x+39=180

−4x+5+−13x+39=180

(−4x+−13x)+(5+39)=180(Combine Like Terms)

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Step 2: Subtract 44 from both sides.

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Step 3: Divide both sides by -17.−17x

−17

=

136

−17

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Answer:

x=−8

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