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3 years ago

A light wave is shone on a glass block at the boundary between air and glass which wave phenomena can been demonstrated

2 answers:

7 0

At the boundary between air and glass, we can see mainly refraction ...
the path of the light bends as it crosses the boundary, and proceeds
from there in a different direction.

If we're very careful and make sensitive measurements, then we can also
detect transmission, some reflection, and a tiny bit of dispersion at the boundary.

Alexeev081 [22]3 years ago

4 0

Answer:

Reflection and Refraction

Explanation:

There are four wave phenomenon that can be observed while studying any wave: reflection, refraction, dispersion, and interference. This depends on the medium of interaction among other factors.

Here two of the wave phenomenon can be observed, namely:

1. Refraction: The phenomenon of bending of light when it passes from one medium to another. So when the light will travel from air to glass, it will divert from its path and bend a little towards the normal. (Normal is an imaginary line drawn perpendicular to the boundary between two mediums)

2. Reflection: Some part of the light will be reflected back from the boundary. It depends on how transparent the glass block is. If it is 100% transparent (which is very nearly impossible to make) there will be no reflection.

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What part do tiny, solid particles in the atmosphere play in cloud formation?

Margarita [4]

Well,

The tiny, solid particles you find in the atmosphere serve as cloud condensation nuclei.

You see, in order for water to condense, the water must have a direct object, grammatically speaking.

Your answer: Tiny, solid particles in the atmosphere play a role in cloud formation by providing the object upon which water may condense to form clouds.

5 0

4 years ago

Explain Resistor in parallel and series.

patriot [66]

$\sf\huge\underline\blue{Resistor:-}$

$\rightarrow$ A resistor is a passive two-terminal electrical component that implements electrical resistance as a circuit element.

$\rightarrow$ Resistors reduce the current flow and lower voltage levels within circuits.

$\sf\large\underline\purple{Resistors \:in\: Series:-}$

$\rightarrow$ A circuit is said to be connected in series when the same amount of current flows through the resistors. In such circuits, the voltage across each resistor is different.

$\rightarrow$ In a series connection, if any resistor is broken or a fault occurs, then the entire circuit is turned off. The construction of a series circuit is simpler compared to a parallel circuit.

$\rightarrow$ For the above circuit(attached image-1), the total resistance is given as:

$\sf{R_{total}\: = \:R1 + R2 + ….. + Rn}$

The total resistance of the system is just the total of individual resistances.

$\sf\large\underline\purple{Resistors \:in\: Parallel:-}$

$\rightarrow$ A circuit is said to be connected in parallel when the voltage is the same across the resistors. In such circuits, the current is branched out and recombines when branches meet at a common point.

$\rightarrow$ A resistor or any other component can be connected or disconnected easily without affecting other elements in a parallel circuit.

$\rightarrow$ The figure(attached image -2) above shows ‘n’ number of resistors connected in parallel. The following relation gives the total resistance here

$\sf{\frac{1}{R_{total}}\: = \:\frac{1}{R1} + \frac{1}{R2} + ….. + \frac{1}{Rn}}$

$\rightarrow$ The sum of reciprocals of resistance of an individual resistor is the total reciprocal resistance of the system.

_______________________________

Hope it helps you:)

6 0

3 years ago

Read 2 more answers

A 15-N force to the left and a 45-N force to the right act on a 10 kg object in opposite directions.

aleksley [76]

Answer:

daddy

Explanation:

6 0

3 years ago

If the sum of all the forces acting on a moving object is zero, the object will:

natita [175]

Answer:

continue moving with constant velocity

Explanation:

4 0

2 years ago

Bare free charges do not remain stationary when close together. To illustrate this, calculate the acceleration of two isolated p

Marta_Voda [28]

Answer:

Acceleration, $a=9.91\times 10^{15}\ m/s^2$

Explanation:

It is given that,

Separation between the protons, $r=3.73\ nm=3.73\times 10^{-9}\ m$

Charge on protons, $q=1.6\times 10^{-19}\ C$

Mass of protons, $m=1.67\times 10^{-27}\ kg$

We need to find the acceleration of two isolated protons. It can be calculated by equating electric force between protons and force due to motion as :

$ma=\dfrac{kq^2}{r^2}$

$a=\dfrac{kq^2}{mr^2}$

$a=\dfrac{9\times 10^9\times (1.6\times 10^{-19})^2}{1.67\times 10^{-27}\times (3.73\times 10^{-9})^2}$

$a=9.91\times 10^{15}\ m/s^2$

So, the acceleration of two isolated protons is $9.91\times 10^{15}\ m/s^2$ . Hence, this is the required solution.

3 0

3 years ago