Answer:
271.862 N/m
Explanation:
From Hook's Law,
mgh = 1/2ke²............... Equation 1
Where
m = mass of the ball, g = acceleration due to gravity, k = spring constant, e = extension, h = height fro which the ball was dropped.
Making k the subject of the equation,
k =2mgh/k²....................... Equation 2
Note: The potential energy of the ball is equal to the elastic potential energy of the spring.
Given: m = 60.3 g = 0.0603 kg, g = 9.8 m/s², e = 4.68317 cm = 0.0468317 m, h = 53.7 cm = 0.537 m
Substitute into equation 2
k = 2(0.0603)(9.8)(0.537)/0.048317²
k = 0.6346696/0.0023345
k = 271.862 N/m
Answer:

Explanation:
<u>Given:</u>
Force = f = 60 N
Mass = m = 12 kg
<u>Required:</u>
Acceleration = a = ?
<u>Formula:</u>
F = ma
<u>Solution:</u>
Rearranging formula
a = F / m
a = 60 / 12
a = 5 ms⁻²
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Hope this helped!
<h3>~AH1807</h3><h3>Peace!</h3>
Answer:
Elastic Potential Energy
Explanation:
Elastic Potential Energy (“Spring Energy”) is the form of energy an object has when it is stretched, compressed, twisted, bent, or otherwise has its shape changed as long as the object resists and will try to return to its original state.
Answer:
The buoyant force is 3778.8 N in upward.
Explanation:
Given that,
Mass of balloon = 222 Kg
Volume = 328 m³
Density of air = 1.20 kg/m³
Density of helium = 0.179 kg/m³
We need to calculate the buoyant force acting
Using formula of buoyant force

Where,
= density of air
V = Volume of balloon
g = acceleration due to gravity
Put the value into the formula


This buoyant force is in upward direction.
Hence, The buoyant force is 3778.8 N in upward.